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erik [133]
2 years ago
5

In which stage of the Calvin cycle does the plant cell produce energy for storage?

Biology
1 answer:
Ludmilka [50]2 years ago
7 0
I believe the answer is the Regeneration stage.
A this stage of the Calvin Cycle, only one of the G3P molecules leaves the cycle and is sent to the cytoplasm to contribute to the formation of other compounds needed by the plant. Because the G3P exported from the chloroplast has three carbon atoms, it takes three "turns" of the Calvin cycle to fix enough net carbon to export one G3P. Each turn makes two G3Ps, therefore three turns make six G3Ps. 
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Two short-tailed Manx cats are bred together. They produce 3 kittens with long tails 5 short tails and 2 without tails. From the
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Answer and Explanation:

There are three phenotypes, so it seems that this an example of incomplete dominance, with the short tail being the intermediate form between long-tail and no-tail. Incomplete dominance is a condition where neither of the alleles completely dominates over the other one. Dominant alleles cannot completely cover up the recessive alleles. Descendents possess an intermediate phenotype between the two parental phenotypes and not the dominant one, which would appear if this would be the case of complete dominance.

<u>Available data:</u>

  • Two short-tailed Manx cats are bred together.
  • F1: 3 kittens with long tails, 5 short tails, and 2 without tails.

The T gene might express the tail trait. T allele expresses long the tail and is dominant over t allele which expresses the absence of the tail.  

So, homozygous dominant individuals, TT, are long-tailed animals

homozygous recessive individuals, tt, have no tail

Heterozygous individuals, Tt, are short-tailed animals, the intermediate form.

Cross: Two short-tailed Manx cats are bred together

Parental)  Tt    x    Tt

Gametes) T   t   T   t

Punnet Square)  T        t

                   T    TT     Tt

                    t     Tt       tt

F1)  1/4 TT = Long-tailed animals

     2/4=1/2 Tt = Short-tailed animals

     1/4 tt = untailed animals

The ratio 3:5:2 of the progeny in the example is close enough to the Mendelian ratio 1:2:1.

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➜ <u>Oxyhaemoglobin</u>.

➜ <u>Carboxyhaemoglobin</u> and as carbonic acid (CO2 dissolved in blood plasma).

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