Answer:
The answer is below
Step-by-step explanation:
Let x represent the number of single cone ice cream and let y represent the number of double cone ice cream.
Since the vendor stocks a maximum of 70 single cones and a maximum of 45 double cones. hence:
0 < x ≤ 70, 0 < y ≤ 45 (1)
The vendor expects to sell no more than 50 ice creams, hence:
x + y ≤ 50
Plotting the constraint using geogebra online graphing tool, we can see that the solution to the problem is at (5, 45)
Since the vendor sells single-cone ice-creams for $3 and double-cone ice-creams for $4.50, hence:
Revenue = 3x + 4.5y
At the point (5, 45), the revenue is:
Revenue = 3(5) + 4.5(45) = $217.5
I think you are right, it is (1,1).
Answer:
a, (x^2)^3 = x^6 = x^2.x^4
b, x^5·x^7 = x^12 = (x^3)^4
c, x^4·x^22 = x^26 = (x^2)^13
d, (x^2)^8 = x^16 = x^2.x^14
e, x^10/x^3 = x^7 = x^20.x^(-13)
f, x^(-3) = x^4.x^(-7)
g, 1/x^(-3) = x^3 = x^4.x^(-1)
Hope this helps!
:)
Answer:
75
Step-by-step explanation:
Answer:
15
Step-by-step explanation:because u add them all up