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2 years ago

What binomial do you have to add to the polynomial:

Mathematics

1 answer:

marshall27 [118]2 years ago

7 0

Answer:

a) $-2x^2+5xy$

b) $-3y^2+5xy$

Step-by-step explanation:

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable x is:

$-2x^2+5xy$

$(2x^2+3y^2-5xy+1)+(-2x^2+5xy)$

$=2x^2+3y^2-5xy+1-2x^2+5xy$

$=2x^2-2x^2+3y^2-5xy+5xy+1$

$=3y^2+1$

Given polynomial : $2x^2+3y^2-5xy+1$

The binomial that should be added to the given polynomial to get a polynomial that does not contain the variable y is:

$-3y^2+5xy$

$(2x^2+3y^2-5xy+1)+(-3y^2+5xy)$

$=2x^2+3y^2-5xy+1-3y^2+5xy$

$=2x^2+3y^2-3y^2-5xy+5xy+1$

$=2x^2+1$

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When twice a certain number is added to 7,the result is less than 17.what is the number.

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3 years ago

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2 years ago

The first 4 terms of a geometric sequence are 2, 6, 18, 54. Part A: Find the common ratio. Remember the common ratio is the numb

ra1l [238]

Answer:

Common ratio is 3

The three terms are 162, 486, 1458

Step-by-step explanation:

Given: The first 4 terms of a sequence are $2,6,18,54$

To find:

A. the common ratio

B. the next 3 values in the geometric sequence

Solution:

Geometric sequence is a sequence in which each of the terms is obtained by multiplying the previous term by a fixed number.

$\frac{6}{2}=3\\\\\frac{18}{6}=3\\\\\frac{54}{18}=3$

So, the common ratio is $3$

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8 0

2 years ago

Bharat and ingrid leave their building at the same time on their bikes and travel in opposite directions. If bharat's speed is 1

yanalaym [24]

Answer:

3 hours

Step-by-step explanation:

speed of Bharat = 12kilometers / hour

speed of Ingrid=14 kilometers / hour

For this problem we'll be using formula relating time, distance and speed.i.e

Distance = speed x time

Suppose Bharat is riding at a distance of 'b' kilometers, therefore time taken by him will be:

Time = distance/ speed

Time= b/12 hours.

Also, Ingrid can ride the distance at this time with speed of 14km/hr

The distance would be,

Distance = speed x time

Distance = 14 x (b/12) => 14b/12

Distance= 7b/6

Let ' $d_{b}$ ' be the distance that Bharat have covered after time 't'

therefore, $d_{b}$ = 12 x t

Let ' $d_{i}$ ' be the distance that Ingrid have covered after time 't'

therefore, $d_{i}$ = 14 x t

In order to find the time when they are 78 kilometers apart, we will add $d_{i}$ and $d_{b}$ , because they are travelling in opposite direction creating distance between them.

So,

$d_{i}$ + $d_{b}$ = 78

( 14 x t) + (12 x t) =78

14t + 12t =78

26t= 78

t= 78/26

t= 3hours.

thus, it will take 3 hours until they are 78 kilometers apart

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3 years ago