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Evgesh-ka [11]
3 years ago
8

Which group on the periodic table are the last reactive? A alkali metals B alkaline earth metals C halogens D noble gases

Chemistry
1 answer:
alexgriva [62]3 years ago
8 0
<h3>Answer:</h3>

D. Noble gases

<h3>Explanation:</h3>
  • Noble gases are elements in the last group of the periodic table.

Why are they the least reactive elements?

  • Noble gases have an octet configuration, which means they have maximum number of electrons in their outermost energy levels.
  • This makes them stable, which means they are inert.
  • Examples of noble gases include neon, argon, krypton, etc.

What is the Trend in reactivity in the periodic table?

Down the group from top to bottom

  • The reactivity of metals in the periodic table increases down the group due the increase in the number of energy levels which makes it easier for them to lose electron(s).
  • Non-metals react by gaining electron(s), therefore, their reactivity decreases down the group because as the energy level increases the nuclear charge decreases.

Across the period from left to right.

  • Reactivity of metals decreases across the period because of an increase in nuclear charge which makes it more difficult for them to lose electron(s).
  • On the other hand, reactivity of non-metals increases across the period due to increased nuclear charge that makes it easier for them to gain electron(s).
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Add a constant temperature when the volume of the gas is decreased what happens to its pressure
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Answer:

<h2>Pressure will increase</h2>

Explanation:

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3.
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Answer:

3. V = 0.2673 L

4. V = 2.4314 L

5. V = 0.262 L

6. V = 2.224 L

Explanation:

3. assuming ideal gas:

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∴ R = 0.082 atm.L/K.mol

∴ V1 = 225 L

∴ T1 = 175 K

∴ P1 = 150 KPa = 1.48038 atm

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(175 K))/((1.48038 atm)(225 L))

⇒ n = 0.043 mol

∴ T2 = 112 K

∴ P2 = P1 = 150 KPa = 1.48038 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(112 K)(0.043 mol))/(1.48038 atm)

⇒ V2 = 0.2673 L

4. gas is heated at a constant pressure

∴ T1 = 180 K

∴ P = 1 atm

∴ V1 = 44.8 L

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(180 K))/((1 atm)(44.8 L))

⇒ n = 0.3295 mol

∴ T2 = 90 K

⇒ V2 = RT2n/P

⇒ V2 = ((0.082 atm.L/K.mol)(90 K)(0.3295 mol))/(1 atm)

⇒ V2 = 2.4314 L

5.  V1 = 200 L

∴ P1 = 50 KPa = 0.4935 atm

∴ T1 = 271 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(271 K))/((0.4935 atm)(200 L))

⇒ n = 0.2251 mol

∴ P2 = 100 Kpa = 0.9869 atm

∴ T2 = 14 K

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(14 K)(0.2251 mol))/(0.9869 atm)

⇒ V2 = 0.262 L

6.a)  ∴ V1 = 24.6 L

∴ P1 = 10 atm

∴ T1 = 25°C = 298 K

⇒ n = RT/PV

⇒ n = ((0.082 atm.L/K.mol)(298 K))/((10 atm)(24.6 L))

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∴ P2 = 101.3 KPa = 0.9997 atm

⇒ V2 = RT2n/P2

⇒ V2 = ((0.082 atm.L/K.mol)(273 K)(0.0993 mol))/(0.9997 atm)

⇒ V2 = 2.224 L

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