What is the temperature of 0.460 mol of gas at a pressure of 1.2 atm and a volume of 12.5 L ? Express your answer using two sign
1 answer:
The temperature is 370K.
The volume of a given fuel pattern is immediately proportional to its absolute temperature at regular pressure (Charles's law). The volume of a given amount of fuel is inversely proportional to its pressure whilst temperature is held steady (Boyle's regulation).
Density is immediately proportional to stress and indirectly proportional to temperature. As stress increases, with temperature constant, density will increase. Conversely when temperature increases, with strain regular, density decreases.
The equations describing those legal guidelines are unique cases of the best gasoline regulation, PV = NRT, wherein P is the pressure of the gas, V is its extent, n is the number of moles of the gas, T is its kelvin temperature, and R is the ideal (common) gas constant.
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Answer:
2.15 mg of uranium-238 decays
Explanation:
For decay of radioactive nuclide-
where N is amount of radioactive nuclide after t time, is initial amount of radioactive nuclide and
is half life of radioactive nuclide
Here ,
and
So,
so, N = 2.446 mg
mass of uranium-238 decays = (4.60-2.446) mg = 2.15 mg