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butalik [34]
3 years ago
6

A chemist adds of a iron(III) bromide solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the che

mist has added to the flask. Round your answer to significant digits
Chemistry
1 answer:
vaieri [72.5K]3 years ago
3 0

Answer:

0.246 kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:

0.3700 L × 2.25 mol/L = 0.833 mol

The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:

0.833 mol × 295.56 g/mol = 246 g

1 kilogram is equal to 1000 grams. Then,

246 g × (1 kg/1000 g) = 0.246 kg

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