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butalik [34]
3 years ago
6

A chemist adds of a iron(III) bromide solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the che

mist has added to the flask. Round your answer to significant digits
Chemistry
1 answer:
vaieri [72.5K]3 years ago
3 0

Answer:

0.246 kg

Explanation:

There is some info missing. I think this is the original question.

<em>A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>

<em />

We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:

0.3700 L × 2.25 mol/L = 0.833 mol

The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:

0.833 mol × 295.56 g/mol = 246 g

1 kilogram is equal to 1000 grams. Then,

246 g × (1 kg/1000 g) = 0.246 kg

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In dilute solutions, the unit osmolarity is being used. It usually has units milliosmols per liter of solution or mOsmol/L. An osmole defines the number of moles of the solute that would have an effect on the osmotic pressure of the solution. Osmolarity is calculated by the product of the molarity and the number of particles in the solution which is 2 for potassium chloride. We calculate as follows:
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