For this case we have that by definition, the equation of a line of the slope-intersection form is given by:
Where:
m: It's the slope
b: It is the cut-off point with the y axis
While the point-slope equation of a line is given by:
Where:
m: It's the slope
It is a point through which the line passes
In this case we have a line through:
(8,4) and (0,2)
Therefore, its slope is:
Its point-slope equation is:
Then, we manipulate the expression to find the equation of the slope-intersection form:
Therefore, the cut-off point with the y-axis is 
ANswer:
A. -25/36
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The answers to the question are are the equations
y = 0.08x²-1.6x+13
y = 0.08(x-10)²+5
<h3>How to solve for the system of equations</h3>
David starts at (20, 13) and skates along a path that can be modeled by a quadratic function with a vertex at (10, 5).
Vertex form of quadratic function is
y = 
13 = a(x-10)²+5
let x = 20
a(20-10)²+5
13 = 100a + 5
take like terms
13 - 5 = 100a
8 = 100a
divide through by 100
a = 0.08
hence the equation would be
y = 0.08(x-10)²+5
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Answer:
6
Step-by-step explanation:
First you would do 6 minus 14 and end up with -8
Then you would do -8 times 3 which equals -24
Lastly you would do -24 divided by -4 and get 6
Answer: 7
Step-by-step explanation:
C = 9
B = 6
Wherever you see a c, you put a 9. Wherever you see a b, you put a 6. If there is already a number in front of the B, multiply it by 6
