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2 years ago

10

Can someone please help me on this. Identify the terms, coefficients, and constants in the expression.

1 answer:

Makovka662 [10]2 years ago

8 0

Answer:

45

Step-by-step explanation:

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The mean clotting time of blood is 7.45 seconds with a standard deviation of 3.6 seconds. what is the probability that an indiv

Usimov [2.4K]

Less than 3 is about 10.75% and greater than 13 is about 6.18%.

To find these percents, you need to find the z-score for each value. Then, use your table to find the correct percent. Be sure to find the side above 13 when you use your chart.

For less than 3:
(3 - 7.45) / 3.6 = -1.24 = The percent below this is 0.1075

For greater than 13:
(13 - 7.45) / 3.6 = 1.54 = The percent above this is 0.0618

7 0

2 years ago

How would you "remove the discontinuity" of f ? in other words, how would you define f(5) in order to make f continuous at 5?f(x

Nataliya [291]

Hope this helps! I'm sorry for worse handwriting.

7 0

2 years ago

Please help I need this in less than an hour

vagabundo [1.1K]

Answer:

A because 72 divided by 8 is 9 and Henry earns $12 per hour and mike get $9 per hour so there is a $3 difference

Step-by-step explanation:

5 0

2 years ago

What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

2 years ago

Plz help ASAP! 10 points

loris [4]

There’s this app called Socratic that you can use. It’s like this one but it’s a little different

4 0

2 years ago