Volume of the prism:
V = B · h, where B stays for the area of the base and h stays for the height of the prism. And we know that d1 = 8, d2 = 6
B = ( d1 · d2 ) / 2 = ( 8 · 6 ) / 2 = 48 / 2 = 24
V = 24 · 16 = 384
Answer:
The volume of the prism is 384 cubic units.
Answer:
answer is:
![y=x^{3}-10 x,y=x^{2}-6](https://tex.z-dn.net/?f=y%3Dx%5E%7B3%7D-10%20x%2Cy%3Dx%5E%7B2%7D-6)
Step-by-step explanation:
we are asked to find which system of equations can we use to find the roots of the equation:
![x^{3}-10x=x^{2}-6](https://tex.z-dn.net/?f=x%5E%7B3%7D-10x%3Dx%5E%7B2%7D-6)
since the system of equation in last part is given as:
![y=x^{3}-10 x,y=x^{2}-6](https://tex.z-dn.net/?f=y%3Dx%5E%7B3%7D-10%20x%2Cy%3Dx%5E%7B2%7D-6)
so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:
.
Using this equation, f(3) = 23.
In order to find the value of f(3), we need to take the f(x) equation and put 3 everywhere we see x. Then we follow the order of operations to solve. So, let's start with the original.
f(x) = 2x^2 + 5sqrt(x - 2)
Now place 3 in for each x.
f(3) = 2(3)^2 + 5sqrt(3 - 2)
Now square the 3.
f(3) = 2(9) + 5 sqrt(3 - 2)
Do the subtraction inside of the parenthesis.
f(3) = 2(9) + 5sqrt(1)
Take the square root
f(3) = 2(9) + 5(1)
Multiply.
f(3) = 18 + 5
And add.
f(3) = 23
Most graphing calculators will do weighted averages pretty easily. It is mostly a matter of data entry.
mx = -2
my = 10
(x, y) = (mx, my)/10 = (-0.2, 1)