The domain are all valid values for x (the independent variable) that can be used in an equation.
We have to look at any potential values of x which won't work. Easily put: in algebra, just look for values of x which cause either division by zero, or the square root of negative numbers.
A couple of examples:
y=2x+4
You can insert any negative or positive value, or zero, for x and get a valid equation. Therefore the domain is the set of all real numbers. Answers are usually written as:
x: {R}, or simply 'all real numbers'.
what about y=2/(x-1)
In this equation, x appears in the denominator. If x-1=0, then division by zero would occur.
Solve: x-1≠0
x≠1
In set notation:
x: (-∞,1)∪(1,∞)
Parentheses are next to the 1, as the domain comes up to 1, but does not include 1.
Read left to right, the domain is "negative infinity to 1, exclusive, in union with 1 to positive infinity"
Answer:
702.1
Step-by-step explanation:
Use the formula for the diagonal of a cuboid.
√(l^2+b^2+h^2)
√(33^2+56^2+33^2)
√5314
= 702.125345
d. both a relation and a function:
Given:
Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In the second assessment he scores 73%. After that, his scores keep increasing by 2% in every assessment.
x represents the number of assessments since he starts recording and y represents the scores in each assessment.
In order for a relation to be a function the association has to be unambiguous that means that for a given input only one output can exist.If an input can have two or more outputs then you cannot determine which is the correct output for that input.
In the given situation:
x is the input that is number of assessments since mark starts recording the scores so there is only one assessment no repeating.so there is only one output.
Hence the relation is a function.
Learn more about the function here:
brainly.com/question/5975436
#SPJ1
Answer:
Step-by-step explanation:
x = 1
(x^2-4x+3=0 or sin(x)=1)
x = 1
( x^2-4x+3=0 or sin(x)=1)
Answer:
60 local calls
Step-by-step explanation:
Total price minus the long-distance charges: 54.35 - 8.35 = $46.00
46 minus the fixed per month cost: 46-31 = $15
15 divided by the cost of each local call: 15/0.25 = 60 calls
