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Fed [463]
1 year ago
7

Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In

the second assessment he scores 73%. After that, his scores keep increasing by 2% in every assessment. Assume that x represents the number of assessments since he starts recording and y represents the scores in each assessment.
A. both a relation and a function
B. a function only
C. a relation only
D. neither a function nor a relation
Mathematics
1 answer:
katovenus [111]1 year ago
4 0

d. both a relation and a function:

Given:

Mark records his science scores in each monthly assessment over a period of 5 months. In the first assessment he scores 76%. In the second assessment he scores 73%. After that, his scores keep increasing by 2% in every assessment.

x represents the number of assessments since he starts recording and y represents the scores in each assessment.

In order for a relation to be a function the association has to be unambiguous that means that for a given input only one output can exist.If an input can have two or more outputs then you cannot determine which is the correct output for that input.

In the given situation:

x is the input that is number of assessments since mark starts recording the scores so there is only one assessment no repeating.so there is only one output.

Hence the relation is a function.

Learn more about the function here:

brainly.com/question/5975436

#SPJ1

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Answer:

y=2e^{sin(x)}

Step-by-step explanation:

Given equation can be  re written as

\frac{\mathrm{d} y}{\mathrm{d} x}-ycos(x)=0\\\frac{\mathrm{d} y}{\mathrm{d} x}=ycos(x)\\\\=> \frac{dy}{y}=cox(x)dx\\\\Integrating  \\ \int \frac{dy}{y}=\int cos(x)dx \\\\ln(y)=sin(x)+c............(i)

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ArbitrLikvidat [17]

Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .

To Find : The correct option between the given ones . To write the compound inequality with integers .

Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .

\red{\tt Case\:1}

⇒ 19 ≥ t + 18 .

⇒ t + 18 ≤ 19 .

⇒ t ≤ 19 - 18 .

⇒ t ≤ 1 = 1 ≥ t . ..................(i)

\red{\tt Case\:2}

⇒ t + 18 ≥ 11 .

⇒ t ≥ 11 - 18.

⇒ t ≥ -7 . ....................(ii)

<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>

\Large\boxed{\green{\bf \red{\longmapsto} 1 \geqslant t \geqslant -7 }}

This means that t is less than or equal to 1 but greater than or equal to (-7) .

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