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Svetllana [295]
3 years ago
11

PLEASE HELP

Mathematics
1 answer:
arsen [322]3 years ago
8 0

Answer:

Equation of line shown in the graph is : x= - 2

Step-by-step explanation:

Given,

a line passing through two points ( -2,2) and ( -2,-3).

We need to use two pint line equation:

y - y1 = (y2 - y1 / x2 - x1 ) (x - x1 )

Here , x1 = -2 ,x2 = -2 , y1 = 2 and y2 = -3

So we can plug corresponding values in the line equation.

We get:    y - 2 = {(-3 - 2) / ( -2 - (-2))} (x - (-2))

         y - 2 = (-5 /0 ) (x + 2)

      0 * (y - 2) = -5 (x+2)

          0 = -5x - 10

        10 = -5x

        x = -10/5 = -2

Hence x= -2 is the equation of line shown in the graph.

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Answer:

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3 years ago
36 is 12% of what number?
Softa [21]
I hope this helps you




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3 years ago
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Dmitriy789 [7]
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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

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3 years ago
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