Answer:
Step-by-step explanation:
Find the sum of the first 42 terms of the following series, to the nearest integer.
2,7,12
Solution
The sum is given by
SUM_n=n/2*(a_1+a_n)
a_n=a_1+(n-1)d
a_1=2, n=42, d=5
The 42nd term is therefore given by
a_42=2+(42-1)5=207
SUM_42=42/2*(2+207)=21*209=4389
The sum of the first 42 terms of the series, therefore, is 4389
Answer:
y = -3/2 x + 4
Step-by-step explanation:
y-4 = -3/2 ( x-0)
y = -3/2 x + 4
In the standard form of quadratic

the discriminant is

In your quadratic, a = 1, b = -9 and c = -10
Now you need to plug these values into the expression for the discriminant.
Answer:
last one
Step-by-step explanation:
the least is 10. so 10 plus one of the number is always greater than the other number. The max is 62. 62 plus any number is greater than the othe