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Nataly [62]
3 years ago
5

HELP ASAP PLSS

Physics
1 answer:
GrogVix [38]3 years ago
4 0

Answer:

Frames of reference.

For measuring the physical quantities you have to rely on something as a reference point or a standard value. In the case of physical quantities that are vectors, and an abstract coordinate system is required to express it clearly.

Let us consider a body located on a ship at some point. We can measure its distance from a ship or from the terrace of the building. Hence, we are assigning a coordinate system with respect to a person standing on the ship and terrace. These coordinate systems are called the frames of reference.

While measuring the distance, both coordinate system gives specific values for the same location with regard to the frames of reference.

When the ship is moving, the person on the terrace observes that his values of the distance change. But the person on the ship did not observe any change with respect to his coordinate system.

Similarly, If a person considers a moving train as his frame of reference where his coordinate system is in motion, he finds the things that are stationary on earth seem to move.

The train is his frame of reference which has a velocity with respect to Earth.

Therefore, anything that is stationary with respect to the ground seems to be in motion with respect to his frame of reference.

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Let r denote the distance between the center of the earth and the center of the moon. What is the magnitude of the acceleration
stepan [7]

Answer:

The magnitude of the acceleration ae of the earth due to the gravitational pull of the moon is \mathbf{3.3187\times10^{-5}}\frac{m}{s^{2}}

Explanation:

By Newton's gravitational law, the magnitude of the gravitational force between two objects is:

F=G\frac{Mm}{r^{2}}(1)

With G the gravitational constant, M the mass of earth, m the mass of the moon and r the distance between the moon and the earth, a quick search on physics books or internet websites give us the values:

M=5.972\times10^{24}\,kg

m=7.34767309\times10^{22}\,kg

r=384400\,km

G=6.674\times10^{-11}\,\frac{N\,m^{3}}{kg^{2}}

Using those values on (1)

F=(6.674\times10^{-11})*\frac{(5.972\times10^{24})(7.34767309\times10^{22})}{(384400\times10^{3})^{2}}

F\approx1.98193\times10^{20}N

Now, by Newton's second Law we can find the acceleration of earth ae due moon's pull:

F=M*ae\Longrightarrow ae=\frac{F}{M}=\frac{1.98193\times10^{20}}{5.972\times10^{24}}\approx\mathbf{3.3187\times10^{-5}}

6 0
4 years ago
The statement that no two electrons in the same atom can have the same four quantum numbers is a restatement of
andreev551 [17]

Answer:

Pauli exclusion principle

Explanation:

Pauli's exclusion principle speaks to the quantum numbers assigned to an electron to describe it's general position and movement. Two electrons can occupy the same energy level (which is described by the first quantum number-the principal quantum number), the orbital angular momentum quantum number (represented by the second number) and magnetic quantum number. electrons that have the same value for all three numbers will have different spins. one will have positive a half while the other has negative a half. Therefore they will never have the same complement of quantum numbers

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Your answer would be 4.0 hz.
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Weight=mass x gravitational force

W=60 x 1/100 x 10
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Acceleration can never be negative true of fales
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