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zloy xaker [14]
3 years ago
10

A 600 N astronaut travels to an asteroid where the gravitational force is one-hundredth that of Earth. What is the astronaut's w

eight on the asteroid?
Physics
1 answer:
timurjin [86]3 years ago
7 0
Weight=mass x gravitational force

W=60 x 1/100 x 10
W=60 x 0.1
W=6N
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I neeed help im so comfused Points Possible: 1, Points Correct: 0 Which group of numbers is listed from greatest to least? -3, -
Alona [7]

The groups aren't well formatted ;

The groups are ;

(-3, -1, 0, 2, 7) ; (9, 7, 6, -5, -4) ; (8, -6, 5, -4, 1) ; (-3, -4, -7, -8, -9)

Answer:

(-3, -4, -7, -8, -9)

Explanation:

Given the following group of numbers :

Evaluating each group of values for which is correctly arranged from greatest to least.

(-3, -1, 0, 2, 7) : - 1 is greater than - 3 (the group isn't arranged from greatest to least)

(9, 7, 6, -5, -4) : - 4 is greater than - 5 ; hence, the group isn't arranged from greatest to least

(8, -6, 5, -4, 1) : 5 is greater than - 6 ; hence, the group isn't arranged from greatest to least

(-3, -4, -7, -8, -9) ; the group of numbers here is arranged from greatest to least ;

(-3 > -4 > -7 > -8 > -9) ; hence, the correct group

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A rocket accelerates upward from rest at a rate of 5 m/s^2. At a height of 1000m, the engines burn out and it coasts the rest of
laila [671]

Answer:

Explanation:

Given

acceleration of rocket(a)=5 m/s^2

At h=1000 m rocket burn out

v^2-u^2=2as

v^2-0=2\times 5\times 1000

v=\sqrt{10^4}=100 m/s

(b) time to reach v=100 m/s

v=u+at

100=0+5\times t

t=\frac{100}{5}=20 s

(c)Rocket maximum altitude

v^2-u^2=2as

here u=100 m/s

v=0

a=9.8 m/s^2

s=\frac{v^2}{2g}

s=\frac{100^2}{2\times 9.8}

[tex]s=510.204

Therefore maximum altitude=510.204+1000=1510.204 m

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The kinetic energy of a point body is defined as the product of (1/2) * (m) * (V ^ 2). Therefore, to find the kinetic energy of a body of mass m = 44Kg and velocity V = 10m / s the operation must be done (1/2) * (44) * (10 ^ 2) which results in 2,200 Joules.
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Answer:

elastic potential energy

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