The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".
According to the question,
Mass of box A,
Mass of box B,
Horizontal force,
From the Newton's law,
→
or,
→
Bu substituting the values, we get
→
→
→
We can see that between the two boxes, the action-reaction pair exist.
then,
→
→
→ (magnitude)
Thus the above solution is appropriate.
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Answer:
its good no need to change anything :))
<span>Answer:
First we need to find the acceleration.
torque on cylinder Ď„ = T * r where T is the string tension;
T = m(g - a) where a is the acceleration of the cylinder. Then
Ď„ = m(g - a)r
But also τ = Iα. For a solid cylinder, I = ½mr²,
and if the string doesn't slip, then α = a / r, so
τ = ½mr² * a/r = ½mra.
Since Ď„ = Ď„, we have
m(g - a)r = ½mra → m, r cancel, leaving
g - a = ½a
g = 3a/2
a = 2g/3 where g, of course, is gravitational acceleration.
We know that v(t) = a*t, so for our cylinder
v(t) = 2gt / 3 â—„ linear velocity
and ω = v(t) / r = 2gt / 3r ◄ angular velocity</span>
One is their traits and their characterists that they have in common