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krek1111 [17]
2 years ago
12

Please help with this

Mathematics
1 answer:
sesenic [268]2 years ago
5 0
What do you need help with ?

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Provide an appropriate response.
aivan3 [116]
I think B i am not 100 sure
5 0
2 years ago
Solve for x.<br><br> 3x - 13 = 2<br><br> (SHOW YOUR WORK)
Eddi Din [679]

3x-13=2

move -13 to the other side

sign changes from -13 to +13

3x-13+13=2+13

3x=2+13

3x=15

divide both sides by 3 to get x by itself

3x/3=15/3

cross out 3 and 3, divide by 3 and then becomes 1*1*x=x

x=15/3

x=5

answer:

x=5

7 0
3 years ago
Pls help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Natasha2012 [34]

Answer:

7. 36     8. 1     9. 21

Step-by-step explanation:

You plug in the variables in the equation.

7.5^{2} +-4^{2} = 41

8. (5-4)^{2} = 81

9. 5+4^{2} =21

6 0
3 years ago
Read 2 more answers
If ln(4x+y)=2x-3,then dy/dx=
Viktor [21]

\ln(4x+y)=2x-3

Differentiate both sides wrt x:

\dfrac{\mathrm d(\ln(4x+y))}{\mathrm dx}=\dfrac{\mathrm d(2x-3)}{\mathrm dx}

By the chain rule, we get

\dfrac1{4x+y}\dfrac{\mathrm d(4x+y)}{\mathrm dx}=2

\dfrac{4+\frac{\mathrm dy}{\mathrm dx}}{4x+y}=2

Solve for \frac{\mathrm dy}{\mathrm dx}:

4+\dfrac{\mathrm dy}{\mathrm dx}=8x+2y

\boxed{\dfrac{\mathrm dy}{\mathrm dx}=8x+2y-4}

4 0
3 years ago
Solve the following triangle in which given sides are<br> a=7 b=7 c=9
blagie [28]
We have an isosceles triangle;
A=opposite angle side a.
B=opposite angle side b.
C=opposite angle side c.

A=B
Method 1:

We can divide the isosceles triangle in two right triangles,
hypotenuse=7
side=9/2=4.5

B=A=arccossine (4.5/7)=49.994799...º≈50º
C/2=90º-50º=40º  ⇒ C=2*40º=80º

Answer:
a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º

Method 2:
Law of cosines:
a²=b²+c²-2bcCosA  ⇒CosA=(a²-b²-c²)/(-2bc)
CosA=(49-49-81) / (-126)=0.642857
A=arco cos (81/126)≈50º

B=A=50º

A+B+C=180º
50º+50º+C=180º
C=180º-100º
C=80º

Answer:

</span>a=7;  A=50º
b=7;  B=50º
<span>c=9;  C=80º</span>

8 0
3 years ago
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