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masha68 [24]
3 years ago
14

Use a calculator to find the approximate value of arccos(0.77).

Mathematics
2 answers:
Inessa [10]3 years ago
5 0

The answer is 0.7.

Hope this helps!

kondor19780726 [428]3 years ago
4 0

Answer:

The answer is ≈ 0.691  or  0.7

Step-by-step explanation:

arccos(0.77) ≈ 0.691  or 0.7

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Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

\frac{sin(x+pi/2)}{cos(x+pi/2)}

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)}  = \frac{cos(x)}{cos(x+\pi/2) }

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)

6 0
3 years ago
Which data set has a median of 15? 9, 17, 13, 15, 16, 8, 12 18, 15, 11, 14, 19, 15, 6 7, 16, 14, 16, 11, 7, 17 18, 9, 19, 16, 6,
ivanzaharov [21]

Answer:

The middle number of the data set or average of the two middle numbers in even numbered sets.

Step-by-step explanation:

A median is the middle point of a data set. We order the numbers from least to greatest and find the number directly in the middle of the list. If there are an even number in the set, then we take an average of the middle two.

The data sets are not separated. However, in the sets you have order them least to greatest each. Then count in from both sides to the middle. That number is the middle.

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3 years ago
Hi...I am taking pre calculus and I'm reallyo lost here..can someone help me?
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3 years ago
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| 6        0 |  -   | - 4   -1 |     =       |   6 + 4       0 + 1 |    =    | 10        1 |
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8 0
3 years ago
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
3 years ago
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