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Alenkinab [10]
2 years ago
15

Subtract these sets of matrix

Mathematics
1 answer:
IrinaK [193]2 years ago
8 0
The procedure is to make the difference of the terms that occupy the same position (column and row):

| - 6    - 4 |      | - 5    5 |              | - 6 + 5      - 4 - 5 |          | -1      - 9 |
| 6        0 |  -   | - 4   -1 |     =       |   6 + 4       0 + 1 |    =    | 10        1 |
| 6        4 |      | 6    - 4 |              |   6 - 6        4 + 4 |          |  0         8 |

Answer: option B.

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dybincka [34]

I suppose you mean

f(x)=\cos(x^2)

Recall that

\cos x=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{x^{2n}}{(2n)!}

which converges everywhere. Then by substitution,

\cos(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^n\frac{(x^2)^{2n}}{(2n)!}=\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n)!}

which also converges everywhere (and we can confirm this via the ratio test, for instance).

a. Differentiating the Taylor series gives

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(starting at n=1 because the summand is 0 when n=0)

b. Naturally, the differentiated series represents

f'(x)=-2x\sin(x^2)

To see this, recalling the series for \sin x, we know

\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}

Multiplying by -2x gives

-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}

and from here,

-2x\sin(x^2)=\displaystyle 2x\sum_{n=0}^\infty(-1)^n\frac{2nx^{4n}}{(2n)(2n+1)!}

-2x\sin(x^2)=\displaystyle 4x\sum_{n=0}^\infty(-1)^n\frac{nx^{4n}}{(2n)!}=f'(x)

c. This series also converges everywhere. By the ratio test, the series converges if

\displaystyle\lim_{n\to\infty}\left|\frac{(-1)^{n+1}\frac{(n+1)x^{4(n+1)}}{(2(n+1))!}}{(-1)^n\frac{nx^{4n}}{(2n)!}}\right|=|x|\lim_{n\to\infty}\frac{\frac{n+1}{(2n+2)!}}{\frac n{(2n)!}}=|x|\lim_{n\to\infty}\frac{n+1}{n(2n+2)(2n+1)}

The limit is 0, so any choice of x satisfies the convergence condition.

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Which expression is equivalent to 2x - 17?
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Answer:

i cannot tell where the seperate numbers are and where the x is multiplication and what numbers are negative. post it agian but put spaces in beetween.

Step-by-step explanation:

remember:

PEMDAS

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E- exponents

M- multiplication

D- division

A- addition

S- subtraction

note:

M, D are tied so do it left to right

A, S are tied so do them left to right

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