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Gnom [1K]
3 years ago
5

Hi...I am taking pre calculus and I'm reallyo lost here..can someone help me?

Mathematics
1 answer:
Karolina [17]3 years ago
3 0
1. Log7 (49)=2
2. Log63(216)=3
3. Log2 (256)=8
4. Log4 (64)= 3
5. Log5 (3125)=5
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Which expression does the fraction 3/8 equal to A. 3 times 8 B. 3 divided by eight C. 8 divided by 3 D. 3 - 8
jek_recluse [69]

Answer:

B. 3 divided by eight

Step-by-step explanation:

3/8  means 3 divided by 8

A fraction bar is division

5 0
3 years ago
Which pairs of angles are alternate interior angles? Select all that apply.
andrezito [222]
<h3>Answers: Choice A and Choice C</h3>

Explanation:

Think of the vertical lines as train tracks (the metal rails).

Stuff between the rails are interior angles.

Angles 3 and 6 are one pair of alternate interior angles because they are on alternating sides of the transversal line. The other pair of alternate interior angles are angles 4 and 5.

Alternate interior angles are congruent when we have parallel lines like this.

7 0
2 years ago
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
2 years ago
Please help. <br> Find the value of h in the triangle.
dybincka [34]
1/2×12m×18.2m=109.2m2
109.2m2÷21.8m÷1/2=10m(nearest whole number)
h=10m
3 0
2 years ago
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Find the critical values
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Answer: this is very hard and i was wondering if there is more info

Step-by-step explanation:

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