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3 years ago

Pls help me with this question.

Mathematics

1 answer:

umka21 [38]3 years ago

8 0

Answer: C

Step-by-step explanation:

The equation is in y=mx+b format. The y is the final amount that you will have to pay. The m in this case is the amount of money that you are paying for each individual month (which is $34.99). The x in this case is the number of months you are paying for (which is 1). And b is the starting fee that you have to pay in order to get a membership in the first place (but will not have to pay after the first month). Thus, seeing as there is 1 month's worth of payment and a starting fee tagged on, y would equal the average total cost for the first month of a gym membership.

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Why do you thing rates are usually written as unit rates

tatyana61 [14]

Rates are usually written in unit because it shows you the amount of something per one of the thing it is being compared to (EX: 5 oz/ 1 pig)

3 0

3 years ago

Find the magnitude of the net electric field at the origin (created by charges q1 and q2).

Readme [11.4K]

The direction of the net magnetic field is $167.36^{\circ}$

<h3>How to find the magnitude?</h3>

$q_1=-4 \mathrm{nC} \text { at }(0.6,0.8)$

$q_2=6 \mathrm{nC}$ at (0.6,0)

$r_1=$ Distance of $q_1$ from origin $=\sqrt{0.6^2+0.8^2}$

$r_2=$ Distance of $q_2$ from origin $=0.6$

$\mathrm{k}=$ Coulomb constant $$=9$ times $10^9 \mathrm{Nm}^2 / \mathrm{C}^2$$

Electric field is given by

$&E_1=\frac{k q_1}{r_1^2} \\$

$&\Rightarrow E_1=\frac{9 \times 10^9 \times 4 \times 10^{-9}}{\sqrt{0.6^2+0.8^2}} \\$

$&\Rightarrow E_1=36 \mathrm{~N} / \mathrm{C}$

$&\theta=\tan ^{-1} \frac{0.8}{0.6} \\$

$&\Rightarrow \theta=53.13^{\circ} \\$

$&E_1=36 \cos 53.13^{\circ} \hat{i}+36 \sin 53.13^{\circ} \hat{j} \\$

$&\Rightarrow E_1=21.6 \hat{i}+28.8 \hat{j}$

$&E_2=\frac{k q_2}{r_2^2} \\$

$&\Rightarrow E_2=\frac{9 \times 10^9 \times 6 \times 10^{-9}}{0.6^2} \\$

$&\Rightarrow E_2=150 \mathrm{~N} / \mathrm{C}$

The charge $q_2$ is on the $\mathrm{x}$ axis itself and it is pointing towards the origin (left side) so the sign will be negative

$E_2=-150 \hat{i}$

Resultant electric field

$&E=E_1+E_2 \\$

$&\Rightarrow E=21.6 \hat{i}+28.8 \hat{j}+(-150 \hat{i}) \\$

$&\Rightarrow E=-128.4 \hat{i}+28.8 \hat{j}$

Magnitude of electric field is given by

$&|E|=\sqrt{(-128.4)^2+28.8^2} \\$

$&\Rightarrow|E|=121.6 \mathrm{~N} / \mathrm{C}$

Magnitude of the net electric field is $121.6 \mathrm{~N} / \mathrm{C}$

Direction is given by

$\theta=\tan ^{-1} \frac{128.4}{28.8}=77.36^{\circ}$

From the -x axis

$(90+77.36)^{\circ}=167.36^{\circ}$

The direction of the net magnetic field is $167.36^{\circ}$

To learn more about magnetic field, refer to:

brainly.com/question/26257705

#SPJ4

6 0

2 years ago

Solve the equation below. Show the steps that lead to your final solution.

Stolb23 [73]

Answer:

this is how u would do it

5(2+1)+6−13=3(3−2)

10+5+6−13=3(3−2)

=2/7

8 0

3 years ago

Solve the linear equations of 2x - y = 4<br> 1 - 3y = -3<br> Please I’m in the middle of a test help

lesantik [10]

Answer:

$x = \frac{8}{3}, y = \frac{4}{3}$

Step-by-step explanation:

Solve for y in the first equation.

$y=\frac{4}{3}$ , replace y with $\frac{4}{3}$

Solve for in the first equation.

$x = \frac{8}{3}, y = \frac{4}{3}$

<em>good luck, hope this helps :)</em>

3 0

3 years ago

Read 2 more answers

Please help! asap <br> d- 5.44

masya89 [10]

Answer:

Step-by-step explanation:

2.72 is the unit rate

5 0

3 years ago