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3 years ago

Rewrite the expression in exponent form. y = log4 2

Mathematics

1 answer:

AlladinOne [14]3 years ago

4 0

Answer:

4y=265

Step-by-step explanation:

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A. 9.49 B. 8.49 C.0 D.72 help asap thank you!

kicyunya [14]

Answer:

A. 9.49

Step-by-step explanation:

Use Pythagorean theorem to find the distance and make a right triangle.

So then..

a² + b² = c²

3² + 9² = c²

c² = 9 + 81

c² = 90

c² = $\sqrt{90}$

c = 9.49

3 0

3 years ago

In the SmallState Lottery, three white balls are drawn (at random) from twenty balls numbered 1 through 20, and a blue SuperBall

nata0808 [166]

Hope this helps but I think there is a 1/4 or a 25% chance of somebody winning a prize.

7 0

3 years ago

What is 37 years converted into hours?

natta225 [31]

There are 24 hrs in a day, and there are 365 days in an year

first step: multiply years with days

37 x 365 = 13505 days in all

second step: multiply days with hrs

13505 x 24 = 324120 hrs

your total is 324120 hrs

hope this helps

6 0

3 years ago

Read 2 more answers

What’s the range of ()=−4|−2|−3

Tpy6a [65]

Answer:

Step-by-step explanation:

4 0

3 years ago

Geometry Question attached below

Soloha48 [4]

I'm sure there's an easier way to do this, but this method does work:

First, AB = CD = CG + GF + FD, so FG = 2.

By the Pythagorean theorem, in triangle AFD we get

$1^2+3^2=A F^2\implies A F=\sqrt{10}$

and in triangle BCG,

$2^2+3^2=BG^2\implies BG=\sqrt{13}$

Angles AFD and EFG form a vertical pair, so they are congruent and have measure

$m\angle EFG=\tan^{-1}3$

Similarly, angles BGC and FGE are congruent and have measure

$m\angle FGE=\tan^{-1}\dfrac32$

Then the remaining angle in triangle EFG has measure

$m\angle FEG=\pi-\tan^{-1}3-\tan^{-1}\dfrac32$

We can solve for the lengths of FE and GE exactly by applying the law of sines:

$\dfrac{\sin\left(\pi-\tan^{-1}3-\tan^{-1}\frac 32\right)}2=\dfrac{\sin\left(\tan^{-1}3\right)}{GE}=\dfrac{\sin\left(\tan^{-1}\frac32\right)}{FE}$

$\implies GE=\dfrac{2\sqrt{13}}3,FE=\dfrac{2\sqrt{10}}3$

Let $s$ be the semiperimeter of triangle ABE, so that

$s=\dfrac{AB+BE+EA}2$

Then according to Heron's formula, the area of triangle ABE is

$\sqrt{s(s-AB)(s-BE)(s-EA)}=\dfrac{25}2$

5 0

4 years ago