Notice that half of the coefficient of x is (1/2)(-4), or -2.
Then x^2 - 4x becomes
x^2 - 4x + 4 - 4 = 0, or (x -2)^2 = 4. Then x = -2 plus or minus 2, and the two roots are 0 and -4.
Thus, add 4 to both sides to obtain x^2 - 4x + 4 = 4.
Ok, let's use N and N'.
N is (-1,-1). N' is (4,6).
From point N, the quadrilateral moves to the right 5 and up 7.
So, N+(5,7)=N'.
Answer:
31
Step-by-step explanation:
Evaluate following the order set out in the acronym PEMDAS
That is parenthesis, exponents, multiplication, division, addition, subtraction
Given
(5 + 1)² - (11 + 3² ) ÷ 4
= 6² - (11 + 9) ÷ 4
= 36 - 20 ÷ 4 ← division before subtraction
= 36 - 5
= 31
Here, x - 2y = 14
x = 14 + 2y
Now, substitute this value into first equation,
4x + 6y = 0
4(14 + 2y) + 6y = 0
56 + 8y + 6y = 0
14y = -56
y = -56/14
y = -4
Substitute it into second equation,
x = 14 + 2(-4)
x = 14 - 8
x = 6
In short, Your Answer would be: (6, -4)
Hope this helps!
I believe the answer is A.
