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3 years ago

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Mathematics

2 answers:

Kipish [7]3 years ago

3 0

The answer would be D because 100 Centimeters equal 1 meter so therefore it would be 200 day's of knitting

9966 [12]3 years ago

3 0

Well there is 100 centimeters in 1 meter so if she were to do One meter each day till she got to two meters it would take her 20 days

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What ratio is represented in the table ?

dezoksy [38]

1. The tables represent a ratio of 3:5. For example, 6 x 3 = 18, and 6 x 5 = 30. Also, 20 x 3 = 60, and 20 x 5 = 100.
2. The table has a ratio of 3:4, so the missing blank is 64.

7 0

3 years ago

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tia_tia [17]

Answer:

$8-6i$

Step-by-step explanation:

Multiply out $(3-i)^2$ in order to find out which expression it is equivalent to.

1) Since the whole quantity is squared, write it out as $(3-i)(3-i)$ .

$(3-i)^2\\(3-i)(3-i)$

2) Multiply binomials by using the FOIL method. Multiply the terms that are listed first in each binomial, then the ones that are listed outermost when looking at both binomials, then innermost, and finally the last terms listed in each binomial. Simplify and combine like terms.

$(3-i)(3-i)\\9 - 3i - 3i + i^2$

$9 - 6i + i^2$

3) $i = \sqrt{-1}$ , so $i ^2$ must be $(\sqrt{-1} )(\sqrt{-1})$ . Thus, $i^2$ is equivalent to -1. Knowing this, simplify and combine like terms.

$9 - 6i + ((-\sqrt{1} )(\sqrt{-1} ))$

$9 - 6i -1\\8 - 6i$

Thus, it is equivalent to $8 - 6i$ .

6 0

3 years ago

120540000 in word form and expanse from

valina [46]

One hundred twenty million five hundred forty thousand

8 0

3 years ago

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A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm

MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x $\geq$ 25.8 upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

F(x,a,b)= $\frac{1}{b-a}$ $a\leq x\leq b$

=1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)= $\frac{x-a}{b-a}$ =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

7 0

3 years ago

76. Currently, your savings for each month is capped at $400. If you start investing all of this into a savings plan earning 1%

Alexxandr [17]

Answer:

10 years and 10 months.

Step-by-step explanation:

The annually interest rate (ia) can be converted by monthly (im) by the equation:

(1 + im)¹² = 1 + ia

(1 + im)¹² = 1 +0.01

(1 + im)¹² = 1.001 (putting ln in both sides)

ln(1 + im)¹² = ln1.001

12*ln(1 + im) = 1.0x10⁻³

ln(1 + im) = 8.33x10⁻⁵(applying "e in both sides)

$e^{ln(1 + im)} = e^{8.33x10^{-5}}$

1 + im = 1.00083

im = 0.00083 = 0.083%

For a investimenting, the final amount (A) can be calculated by:

$A = R*(\frac{(1+i)^n-1}{i} )$

Where R is the amount invested per month, i is the interest, and n the number of months:

160000 = 400 * $\frac{(1 +0.00083)^n - 1}{0.00083}$

$\frac{(1 +0.00083)^n - 1}{0.00083}$ = 400

1.00083ⁿ - 1 = 0.332

1.00083ⁿ = 1.332 (applying ln in both sides)

n*ln1.00083 = ln1.332

8.3x10⁻⁴n = 0.2867

n = 345.4 months

345.4 months *1 yea12 months = 10 years and 10 months.

7 0

3 years ago

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