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guapka [62]
3 years ago
6

A high school basketball team won 36% of the games that it played last season. The team won exactly 9 games last season. What is

the total number of games that the team played?
Mathematics
1 answer:
AnnyKZ [126]3 years ago
4 0

Answer: REMEMBER TO RATE 5 STARS AND GIVE ME A HEART, THANKS!!!

The High Shcool Basketball team played a total of 25 games.

Step-by-step explanation:

You take the 9 from the games they won last season and divide it by .36 and that will give you the answer of 25. So 25 is the total games the "High School Basketball Team" won. If you want to double check your answer you can take the answer of 25 and times it by .36 which will equal 9.

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Find the sum of 2/5 and 4/10
chubhunter [2.5K]

Answer:

2/5+4/10

first find the LCM =10

Mytiply both numerator and denominator to have the denominator same value 2×2/5×2 + 4×1/10×1=

4/10 + 4/10 add numerator 8 / 10 both number divisible by 2 answer is 4/5

3 0
3 years ago
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A farmer has both sheep and chickens on his farm. All the animals have the expected number of parts. When his animals are all
lora16 [44]

Answer:

13 sheep, 19 chicken

Step-by-step explanation:

You can start to solve this problem by assigning variables. First, let's assign the number of sheep there are as x and the number of chickens there are as y.

Because each sheep has 4 legs, the number of legs for each sheep would be 4x. Similarly, because each chicken has 2 legs, the number of legs for each chicken would be 2y. Each animal would have 1 head, so the number of heads would just be x and y. Because the number of legs in total are 90, 4x + 2y=90. Because the number of heads in total are 32, x+y=32.

There is now a system of equations with two unknown variables and two equations. There are many ways to solve this, but for me, the easiest would be elimination. First, I would double the second equation, 2x+2y=64. Then, I would subtract that from the first equation, eliminating y. 2x=26. Solving for x gives 13. We can then plug that value into the second equation, making y be 32-13=19. This means that x=13 and y=19, meaning that there are 13 sheep and 19 chicken.

7 0
2 years ago
NEED HELP ASAP
VLD [36.1K]

the perimeter of each side is 5 so the answer is 20

3 0
3 years ago
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You sell your bicycle to your friend for 65$ your friend gives you x five dollar bills and y ten dollar bills. There are a total
jeka94

Answer:

There are 5 five dollar bills and 4 ten dollar bills.

Step-by-step explanation:

Given:

Selling price of bicycle =\$65.

The friend gave x five dollar bills and y ten dollar bills.

Total number of bills =9.

To find: Number of five dollar bills and ten dollar bills the friend gave.

Solution:

The friend gave x five dollar bills and y ten dollar bills and the friend gave 9bills in all.

So, x+y=9.

\Rightarrow x=9-y   ...(i)

Selling price of bicycle =\$65.

So, 5x+10y=65...(ii)

Putting the value of x from equation (i) in equation (ii).

\Rightarrow 5(9-y)+10y=65

\Rightarrow 45-5y+10y=65

\Rightarrow 45+5y=65

\Rightarrow 5y=65-45

\Rightarrow 5y=20

\Rightarrow y=\frac{20}{5}

\Rightarrow y=4

Now, putting the value of y in equation (i).

\Rightarrow x=9-4

\Rightarrow x=5

Hence, there are 5 five dollar bills and 4 ten dollar bills.

5 0
3 years ago
2^2 times 2^3<br> a.2^4<br> b.2^5<br> c.2^6<br> d.4^6
maxonik [38]

Answer:

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

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5 0
3 years ago
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