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3 years ago

Which of the following pairs of values for x and y would

Mathematics

2 answers:

Alchen [17]3 years ago

6 0

Answer: A

Step-by-step explanation:

jarptica [38.1K]3 years ago

3 0

Answer:

your answer is right y=11 x=3

Step-by-step explanation:

y-4=7

y=7+4

y=11

2x+3=9

2×=9-3

2x=6

$\frac{2x}{2} = \frac{6}{2}$

x=3

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Write the equation of the line that passes through the points (4, -6) and (-2,3).

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In point slope form, the answer would be y = - 3/2 x it’s one fraction

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3 years ago

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In the figure below, the segments overline RS and overline RT are tangent to the circle centered at Given that OS = 3.6 and RT =

ExtremeBDS [4]

Answer:

RS = 4.8

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From the Pythagorean Theorem we know:

OR^2 = ST^2 + OT^2

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2 years ago

Is the ratio 4.2:1.5 proportional to the rational 12.6:4.5

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Answer:

YES

Step-by-step explanation:

cause 12.6 / 4.5 = 2.8

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3 years ago

A circle has the equation 2x²+12x+2y²−16y−150=0.

KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

$(x-h)^{2} +(y-k)^{2}=r^{2}$ (1)

Where $(h,k)$ are the coordinates of the center and $r$ is the radius.

Now, we are given the equation of this circle as follows:

$2x^{2}+12x+2y^{2}-16y-150=0$ (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

$2(x^{2}+6x+y^{2}-8y-75)=0$ (3)

Rearranging the equation:

$x^{2}+6x+y^{2}-8y=75$ (4)

$(x^{2}+6x)+(y^{2}-8y)=75$ (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of $(a\pm b)^{2}=a^{2}\pm+2ab+b^{2}$ :

For the first parenthesis:

$x^{2}+6x+b^{2}$

We can rewrite this as:

$x^{2}+2(3)x+b^{2}$

Hence in this case $b=3$ and $b^{2}=9$ :

$x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}$

For the second parenthesis:

$y^{2}-8y+b^{2}$

We can rewrite this as:

$y^{2}-2(4)y+b^{2}$

Hence in this case $b=-3$ and $b^{2}=9$ :

$y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}$

Then, equation (5) is rewritten as follows:

$(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16$ (6)

Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.

Rearranging:

$(x-3)^{2}+(y-4)^{2}=100$ (7)

At this point we have the circle equation in the center radius form $(x-h)^{2} +(y-k)^{2}=r^{2}$

Hence:

$h=-3$

$k=4$

$r=\sqrt{100}=10$

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3 years ago

If f(x) = 7x − 1, what does f(12) represent?

Rasek [7]

Hello :
f(12) represent : B. The value of (7x − 1) when x = 12

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