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Andreas93 [3]
2 years ago
7

X:0,6=6:96 can you help me, please?

Mathematics
1 answer:
navik [9.2K]2 years ago
4 0
Assuming the European decimal notation (using a comma), then
X:0.6=6:96
Multiply left side by 160
160X: 96 = 6:96
=>
160X=6
X=6/160=3/80
Answer :  X=3/80 (=0.0375)
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-4x/7>10 choose the solution set.
wolverine [178]

Answer:

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3 0
3 years ago
A hose is leaking water at a rate of 2 oz/h. How many cups of water will leak out after 2 weeks?
Over [174]

Answer:

84 cups of water will leak out after 2 weeks

Step-by-step explanation:

* Lets how many how to change oz to cup

- One cup contains 8 oz

- We can use the ratio to solve this problem

- A hose is leaking water at a rate of 2 oz/h

- We need to find how many cups of water will leak out after 2 weeks

∵ The rate of the water leak out is 2 oz/hr

∵ 1 cup contains 8 oz

∴ 1 oz = \frac{1}{8} cup

∴ 2 oz = 2 × \frac{1}{8} = \frac{2}{8} = \frac{1}{4} cup

∴ The rate of the water leak out = \frac{1}{4} cup/h

∵ 1 day = 24 hours

∵ 1 week = 7 days

∴ 1 week = 7 × 24 = 168 hours

∵ The number of hours in 1 week is 168

∴ The number of hours in 2 weeks = 168 × 2 = 336 hours

⇒    cups    :    hours

⇒      \frac{1}{4}         :   1

⇒     x         :    336

- By using cross multiplication

∴ x = 336 × \frac{1}{4}

∴ x = 84

- x represents the number of cups of water leak out

<em>84 cups of water will leak out after 2 weeks</em>

5 0
3 years ago
Solve the proportion. When necessary, round to the nearest tenth? 36/j = 7/20​
erastovalidia [21]

Work is provided in the image attached.

3 0
3 years ago
Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

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The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
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yanalaym [24]

Answer:

70

Step-by-step explanation:

7 and 10 = 70, This is the correct answer because 7 times 10 equals 70, and 10 times 7 equals 70 too, so 70 is the LCD

7 and 10 = 1, This is impossible because anything multiplied by 7 naturally does not get 1 as a answer, including 10 too. X

7 and 10 = 10, Only 10 times 1 equals 10, but 7 a natural whole number does not equal 10. X

7 and 10 = 35, Only 7 times 5 equals 35, but 10 times a whole number does not equal 35. X

4 0
3 years ago
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