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Liono4ka [1.6K]
3 years ago
15

Which point-slope equation represents a line that passes through (3, –2) with a slope of negative StartFraction 4 Over 5 EndFrac

tion?
y – 3 = –(x + 2)
y – 2 = (x – 3)
y + 2 = –(x – 3)
y + 3 = (x + 2)
Mathematics
2 answers:
goblinko [34]3 years ago
7 0

Answer:

It's C

Step-by-step explanation:

Got it right on Edg

Schach [20]3 years ago
5 0

Answer:

y + 2 = (-4/5)(x - 3)

Step-by-step explanation:

Your slope is -4/5.  Your line passes through (3, -2).

Applying the point slope formula, we get:

y + 2 = (-4/5)(x - 3)

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A(n - 3) +8= bn for n please help me
Papessa [141]

Given equation: A(n - 3) +8= bn.

Solution: On the left side of the equation we have A(n-3).

We don't have any sign in between A and parenthesis (n-3).

So, we need to multiply A and (n-3).

We need to apply distributive property to multiply A and (n-3).

Distributing A over (n-3), we get

A(n-3) = A*n - 3*A = An -3A.

Substituting this value in original equation,

An -3A +8= bn.

We need to solve it for n, so we get n terms on a side.

We have An on left side, we need to get rid n from left side.

Subtracting An from both sides, we get

An -3A +8-An= bn-An.

-3A +8 = bn - An.

We can see n is a common factor on rigth side in bn-an.

Factoring out n on right side from bn-an.

-3A +8 = (b - A)n.

Dividing both sides by (b-A),

\frac{(-3A+8)}{(b-A)} = \frac{(b-A)n}{(b-A)}

On right (b-A) paranthiss cancelled and we get n on right side.

\frac{(-3A+8)}{(b-A)} =n   Final answer.

So, that would be our final answer

n = (-3A+8)/(b-A)

7 0
3 years ago
If two of the four expressions x + y, x + 5y, x – y, and 5x – y are chosen at random, what is the probability that their product
storchak [24]

Answer:

  1/6

Step-by-step explanation:

The product will only be of the required form if the two chosen factors are of the form (x +by) and (x -by).

For the factor (x+y), there is also a factor (x-y) on the list. For the factor (x+5y), there is no factor (x-5y) available.

So, of the (4·3)/2 = 6 possible ways to choose two expressions from the four given expressions, only one pair of the 6 will have a product of the required form.

The probability is 1/6.

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Step-by-step explanation:

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