Answer:
a) The variable, M represents the amount of fish Ms. Montesinos has
b) The set equation is 11 + 2 = 3 × M - 2
c) 5
Step-by-step explanation:
The given parameters are;
The number of fishes in Ms. Cruz's tank = 11 fishes
The number of fishes Ms, Cruz has after buying two more fishes = 3 × The amount of fish Ms. Montesinos has - 2 fishes
a) Let the variable, M represent the amount of fish Ms. Montesinos has
b) The set up equation is as follows;
11 + 2 = 3 × M - 2
c) From the equation, 11 + 2 = 3 × M - 2, we have;
13 = 3·M - 2
3·M = 13 + 2 = 15
3·M = 15
M = 15/3 = 5
M = 5
The number of fishes Ms. Montesinos has is 17 fishes
Answer:
Step-by-step explanation:
Alright, lets get started.
The given equation is :

Subtracting 1 in both sides


Dividing 2 in both sides


Taking log on both sides


Plugging the value of log e as 1

..................... Answer
Hope it will help :)
144.44 in² is the closest amount of paper she will use to wrap the gift.
Solution:
The given net is the shape of the cylinder.
Diameter of the circle = 4 in
Radius of the circle = 4 ÷ 2 = 2 in
Width of the container = 10.5 in
Length of the container is same as the circumference of the circle.
Area of the circle = 
= 
= 12.56 in²
Area of the 2 circles = 2 × 12.56 = 25.12 in²
Area of the rectangle = circumference × height
= 
= 
= 131.88 in²
Area of the net of the container
= Area of the circles + Area of the rectangle
= 12.56 in² + 131.88 in²
= 144.44 in²
Area of the net of the container = 144.44 in²
Hence 144.44 in² is the closest amount of paper she will use to wrap the gift.
10 × 2 tens = 20 tens = 200
It equals 3.14 (: Hope this helps