Ask question

Ask question

All categories

3 years ago

7

I choose image 2 and it’s a reflection I just need an explanation for it

1 answer:

BartSMP [9]3 years ago

6 0

If you’re doing reflection than you would choose 1 and you explain that you are reflecting over the origin and the (x,y) values for each point of ABC will become (-x,-y) which matches Shape 1

You might be interested in

Y = -4× - 5<br>y = -4× + 5

balu736 [363]

6y = -24

y = -24/6

y = -4

I guess is the answer

7 0

3 years ago

I NEED HELP PLS THIS IS DUE IN 3 HOURS

Mariulka [41]

Answer:

Part 1) $x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2) $x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

Part 1)

in this problem we have

$x^{2} -2x-2=0$

so

$a=1\\b=-2\\c=-2$

substitute in the formula

$x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}$

therefore

$x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))$

$x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})$

Part 2)

in this problem we have

$x^{2} -6x+4=0$

so

$a=1\\b=-6\\c=4$

substitute in the formula

$x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}$

$x=\frac{6(+/-)\sqrt{20}} {2}$

$x=\frac{6(+/-)2\sqrt{5}} {2}$

$x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}$

$x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}$

therefore

$x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))$

$x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})$

5 0

4 years ago

I don't know this please help this Is due tomarrow

Alenkinab [10]

Hi!!

1) 2/3 *12
You basically do this
2/3 * 12/1 = 24/3 which = 8!

2) 13 * 1/2
= 13/1 * 1/2
= 13/2
= 6 1/2
Hope this helps!

5 0

3 years ago

If four angles of a convex pentagon measure 120°, 93°, 108°, and 101°, find the measure of the fifth angle. Show equations and w

olga nikolaevna [1]

It is given in the question that

If four angles of a convex pentagon measure 120°, 93°, 108°, and 101°, find the measure of the fifth angle.

First we have to find the sum of measurement of all the angles of a convex pentagon, by using the formula

$=(n-2)*180$

Where n is the number of sides. And for polygon, it is 5 .SO the sum of measurement of angles of a polygon is

$=(5-2)*180 = 540 \degree$

Let the measurement of missing angle be x .

So we have

$120+93+108+101+x=540$

$422+x =540$

$x=540-422=118$

7 0

3 years ago

The length of Jeff Koon's sculpture is 4 feet more than the width. If the length of the sculpture is 8 feet, what is the area of

Mrrafil [7]

(8+4)x8= 96 feet squared

(There is no little 2 to put in so I just wrote squared)

3 0

3 years ago