Plz help, I am so confusedd

*help please* What is the amplitude of the function graphed?

Vladimir [108]

Answer:

i think -1

Step-by-step explanation:

bc if u look at the picture

7 0

3 years ago

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I have 11 red marbles and 4 blue marbles in a bag if I choose one what color will it be

Veronika [31]

Answer:

11/15 red, 4/15 blue

Step-by-step explanation:

There are 15 marbles in all so that is the denominator.

The numerator is the number of marbles for each color.

So...

11 red marbles / 15 total marbles

4 blue marbles / 15 total marbles

5 0

3 years ago

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Which situation could this graph represent?

HACTEHA [7]

Situation: The answer is D because running up a hill first takes less time, which you can see in the graph. Then, walking up a hill takes more time and you are going upward, which is expressed in the graph. Next, you run down the hill, which takes less time than walking which is on the graph. Finally, you walk the remainder of the hill downwards, which takes more time and is shown in the graph. Hope this helps!

7 0

2 years ago

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Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side

lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

=cot x (sec²x)²

=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]

= cot x(1+ 2 tan²x +tan⁴x)

=cot x+ 2 cot x tan²x+cot x tan⁴x

=cot x +2 tan x + tan³x [ ∵cot x tan x $=\frac{ \textrm{tan x }}{\textrm{tan x}}$ =1]

=R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

L.H.S =(sin x)(tan x cos x - cot x cos x)

= sin x tan x cos x - sin x cot x cos x

$=\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}$

= sin²x -cos²x

=1-cos²x-cos²x

=1-2 cos²x

=R.H.S

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

= $1+\frac{{sin^2x}}{cos^2x}$ [ $\textrm{sec x}=\frac{1}{\textrm{cos x}}$ ]

=1+tan²x $[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]$

=sec²x

=R.H.S

4.

$\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}$

L.H.S= $\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}$

$=\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}$

$=\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}$

$=\frac{\textrm{2sin x}}{sin^2 x}$

= 2 csc x

= R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

= sec²x-tan²x

= $\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}$

$=\frac{1- sin^2x}{cos^2x}$

$=\frac{cos^2x}{cos^2x}$

=1

8 0

3 years ago

Connor took out a 4 year loan to buy a car at a 4% simple interest rate. if he has to pay $240 in interest, how much principal d

uysha [10]

Answer:

The principal borrow for loan is $1,500 .

Step-by-step explanation:

Given as :

The interest paid on simple interest = s.i = $240

The rate of simple interest applied = r = 4%

The time period for loan = t = 4 years

Let The principal borrow = $p

Now,<u> from Simple Interest method</u>

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or. s.i = $\dfrac{\textrm p\times \textrm r\times \textrm t}{100}$

Or, $240 = $\dfrac{\textrm p\times \textrm 4\times \textrm 4}{100}$

Or, $240 × 100 = 16 × p

Or, $24000 = 16 × p

∴ p = $\dfrac{24000}{16}$

i.e p = $1,500

So, The principal borrow for loan = p = $1,500

Hence, The principal borrow for loan is $1,500 . Answer

3 0

3 years ago