First do parenthesis the multiplication then add
9+15=24*3=72+2=74 :)hope this helps
Answer:
The answer will be 7,-3
Step-by-step explanation:
Answer:
1 or 5
Step-by-step explanation:
Given the function h(x)=(2x−2)(x−5)
The zeros of h(x) are the values of x for which h(x)=0
h(x)=(2x−2)(x−5)=0
Note that if a.b=0, either a=0 or b=0.
Appying the above,
If (2x−2)(x−5)=0
Then:
2x−2=0 or x-5=0
2x=2 or x=5
x=1 0r 5
The zeroes of h(x) as defined are 1 or 5.
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
Answer:
Letter B the second one
Step-by-step explanation:
