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Anna71 [15]
3 years ago
10

Where could point E be and D is between E and B?

Mathematics
1 answer:
Butoxors [25]3 years ago
6 0
It is d.2. because its like a pattern you have to follow on the graph.
You might be interested in
Solve for t.<br> -t = 9(t-10)<br> pls help
g100num [7]

Step-by-step explanation:

-t = 9(t-10)

-t = 9t - 90

90 = 9t + t

90 = 10t

90 ÷ 10 = t

9 = t

6 0
3 years ago
What numbers multiply to 0.32 and also add to 1.2
mylen [45]
.08 x .04 is the right answer

6 0
3 years ago
What is (-7/8)(-3/4) simplified
Snowcat [4.5K]

Answer:

<h2>21/32</h2>

Step-by-step explanation:

-7/8 × -3/4 = 21/32

-7 × -3   = 21  

-8 × -4   = 32

21/32

<u><em>IMPORTANT: This number is not negative, because a negative times a negative is a positive.</em></u>

By the way, if you didn't know how to arrive at the fraction here's how.

First, Address input parameters & values.

Input parameters & values: The decimal number = 0.65625. Then, write it as a fraction

0.65625/1

Multiply by 100000 both the numerator & denominator

(0.65625 x 100000)/(1 x 100000) = 65625/100000

65.625% = 65.625/100 or 65625/100000

Find LCM (Least Common Multiple) for 65625 & 100000.

3125 is the LCM for 65625 & 100000

Divide by 3125

65625/100000 = (65625 / 3125) / (100000 / 3125)

= 21/32

I'm always happy to help :)

7 0
3 years ago
Read 2 more answers
Please i beg u help me, this will mean a lot!
slega [8]

Answer:

17

Step-by-step explanation:

Mode is the number that appears the most

3 0
2 years ago
If f(x) = x + 4 and g(x)=x^2-1, what is m(g o f)(x)?
Andreas93 [3]

Until now, given a function  f(x), you would plug a number or another variable in for x. You could even get fancy and plug in an entire expression for x. For example, given  f(x) = 2x + 3, you could find f(y2 – 1) by plugging y2 – 1 in for x to get f(y2 – 1) = 2(y2 – 1) + 3 = 2y2 – 2 + 3 = 2y2 + 1.

In function composition, you're plugging entire functions in for the x. In other words, you're always getting "fancy". But let's start simple. Instead of dealing with functions as formulas, let's deal with functions as sets of (x, y) points:

Let f = {(–2, 3), (–1, 1), (0, 0), (1, –1), (2, –3)} and  

let g = {(–3, 1), (–1, –2), (0, 2), (2, 2), (3, 1)}.  

 

Find (i) f (1), (ii) g(–1), and (iii) (g o f )(1).

(i) This type of  exercise is meant to emphasize that the (x, y) points are really (x, f (x)) points. To find  f (1), I need to find the (x, y) point in the set of (x, f (x)) points that has a first coordinate of x = 1. Then f (1) is the y-value of that point. In this case, the point with x = 1 is (1, –1), so:

8 0
3 years ago
Read 2 more answers
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