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alexira [117]
3 years ago
13

An investor invested a total of ​$1900 in two mutual funds. One fund earned a 7​% profit while the other earned a 4​% profit. If

the​ investor's total profit was ​$51​, how much was invested in each mutual​ fund? The amount invested in the mutual fund that earned 7​% was?
Mathematics
1 answer:
Minchanka [31]3 years ago
7 0
You have to add the numbers
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Can someone help me with this question please?
blagie [28]
Not sure but i guess 25 %ile is 55/4=13.75 and 80%ile=80*55/100=44
                
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3 years ago
The chances that it will rain tomorrow are 20% what are the chances that it will not rain?
balandron [24]
Hey!~

The chances that it will not rain "tomorrow" is 80%

Hope this helps and have a great day!

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5 0
3 years ago
Y=-2x²-8x-5 domain and range
Jobisdone [24]

Answer:

Domain: All real numbers

Range: y≤3

Step-by-step explanation:

The given function is

y =  - 2 {x}^{2}  - 8x - 5

This is a polynomial function.

The domain is set of all values of x, that makes this function defined.

Since polynomial functions are defined everywhere, the domain is all real numbers.

To find the range we put the function in vertex form:

y =  - 2( {x}^{2}  + 4x) - 5

y =  - 2( {x}^{2}  + 4x + 4) - 5 +  - 4 \times  - 2

y =  - 2( {x}  + 2)^{2} - 5 + 8

y =  - 2( {x}  + 2)^{2}  +  3

The maximum value is 3

The function turns downward, hence the range is:

y \leqslant 3

6 0
3 years ago
Help me fill in the blanks<br><br> 6x + __ =3<br> (__ + 5)
Virty [35]

Answer:

<u>15</u>

<u>2x</u>

Step-by-step explanation:

4 0
3 years ago
URGENT HELP PLEASE!
Vaselesa [24]

Answer:

(a) x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b) x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}

Step-by-step explanation:

It is given that 0\leq x\leq 2\pi.

(a)

\sqrt{2}\sin 2x=1

\sin 2x=\dfrac{1}{\sqrt{2}}

\sin 2x=\dfrac{\pi}{4}

2x=\dfrac{\pi}{4},\dfrac{3\pi}{4},\dfrac{9\pi}{4},\dfrac{11\pi}{4}     [\because \sin x=\sin y\Rightarrow x=n\pi+(-1)^ny]

x=\dfrac{\pi}{8},\dfrac{3\pi}{8},\dfrac{9\pi}{8},\dfrac{11\pi}{8}

(b)

\csc^2 x-\csc x-2=0

\csc^2 x-2\csc x+\csc x-2=0

\csc x(\csc x-2)+1(\csc x-2)=0

(\csc x+1)(\csc x-2)=0

\csc x=-1\text{ or }\csc x=2

\sin x=-1\text{ or }\sin x=\dfrac{1}{2}         [\because \sin x=\dfrac{1}{\csc x}]

x=\dfrac{3\pi}{2}\text{ or }x=\dfrac{\pi}{6},\dfrac{5\pi}{6}

Therefore, x=\dfrac{3\pi}{2},\dfrac{\pi}{6},\dfrac{5\pi}{6}.

5 0
3 years ago
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