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Lesechka [4]
3 years ago
8

We will flip a balanced coin 3 times and for each toss, record whether we get a Head or a Tail. Write all possible outcomes of t

his experiment to find the probability that we get exactly 1 tail.
a. 2/3
b. 1/8
c. 1/3
d. 3/8
Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0

Answer: A- 2/3

Step-by-step explanation:

Possible outcomes when a coin is tossed 3 times is 1/2 + 1/2+ 1/2= 3/2

Probability of getting exactly one tail=

3/2x=1

x=1÷3/2

=1 ×2/3

=2/3

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If angles are congruent, solve by setting expressions equal to each other.<br><br> True<br> False
Taya2010 [7]
Answer: True, angles that are congruent are equaled to each other
3 0
3 years ago
What is the value of the numerical expression 5/8-5/12(3-1/4)+2/3
vlabodo [156]
Make bottom numbers same
find least common multipules of 8,12,4 and 3
8=2 times  2 times 2
12=2 times 2 times 3
4=2 times 2
3=3
lcm=2 times 2 times 2 times 3=24

5/8 times 3/3=15/24
5/12 times 2/2=10/24
3/1 times 24/24=72/24
1/4 times 6/6=6/24
2/3 times 8/8=16/24
we now have
15/24-10/24(72/24-6/24)+16/24
pemdas
simplify parenthasees first
72/24-6/24=66/24

now we have
15/24-10/24(66/24)+16/24
multiply
15/24-660/576+16/24
make same bottom number
15/24 times 24/24=360/576
16/24 times 24/24=384/576
360/576-660/576+384/576
84/576
7/48

answer is 7/48
3 0
3 years ago
How many hours would someone who earns 6.25 per hour have to work to earn 225.65
Mars2501 [29]

That comes to 225.65 /  6.25

= 36.1 hours

6 0
3 years ago
How do I solve this? (Geometry)
irga5000 [103]

7x4 = 28

5 x z = 28

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6 0
3 years ago
Using synthetic division, find (x4 − 2) ÷ (x + 1).
Fiesta28 [93]

Answer:

Step-by-step explanation:

We have given:

x^4-2/x+1

Put x+1 = 0

x= 0-1

x= -1

-1 | 1   0   0   0   -2

  |      -1   1   -1     1

_______________

    1    -1   1  -1    -1

Thus it makes the expression:

x^3-x^2+x-1 - 1/x+1

You can further confirm this expression by solving the expression:

(x4 − 2) ÷ (x + 1).

x^4 - 1 -1/x+1

x^4-1/x+1 - 1/x+1

(x^2-1) (x^2+1)/x+1 - 1/x+1

(x-1)(x+1) (x^2+1)/x+1  - 1/x+1

x+1 n the numerator will be cancelled out by x+1 in the denominator.

(x-1) (x^2+1) - 1/x+1

Multiply (x^2+1) by x-1

x(x^2+1) -1(x^2+1)  - 1/x+1

x^3+x-x^2-1 - 1/x+1

x^3-x^2+x-1 - 1/x+1 ....

6 0
3 years ago
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