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Furkat [3]
3 years ago
5

Find f (2b^2) for (x)=x^2-4x

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

Answer:

A

Step-by-step explanation:

We are given the function:

f(x) = x^2 - 4x

And we want to find:

\displaystyle f(2b^2)

Substitute:

\displaystyle f(2b^2) =(2b^2)^2 -4(2b^2)

And evaluate:

\displaystyle \begin{aligned}  f(2b^2) &=(2b^2)^2 -4(2b^2) \\ &=(4b^4) +(-8b^2) \\ &= 4b^4 - 8b^2 \end{aligned}

In conclusion, our answer is A.

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Answer:

Step-by-step explanation:

We have that the focus is at (p,0) and that the directrix is x=-p. Take the point (-p,0) of the directrix. We know that the vertex of the parabola is at the middle point ot the line segment that joins the points (p,0) and (-p,0). To get the middle piont, we take the average coordinate by coordinate. That is, the middle point is (\frac{-p+p}{2}, \frac{0+0}{2}) = (0,0). The general formula of a parabola of vertex (h,k) that opens to the right or to the left is given by

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y^2 = 4px

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