Consider c as the cost of the widget so that our given equation is
c = 0.1w^2 + 20w
Take the derivate of the equation.
d/dt (c = 0.1w^2 + 20w)
dc/dt = 0.2w + 20
Given dc/dt = $16000 per month, the number of widgets would contain:
16000 = 0.2w + 20
-0.2w = 20 - 16000
-0.2w = -15980
w = 79900 widgets
Answer:
Step-by-step explanation:
Are you in Calculus? These are calculus concepts!
To calculate the rate of change here you must specify an interval, e. g., "what is the rate of change on the interval (0, 3)?"
If you know calculus: The 'rate of change' on the interval (a, b) is
f(b) - f(a)
r. of c. = --------------------
b - a
Have you used this formula before?
Because of the 'x^2' term this is NOT a linear function.
If you want more explanation, provide an interval on which you want the average rate of change and ask specific questions of your own.
"T is a subset of P"
Not true since triangle has three sides but parallelogram has four sides.
"E is a subset of I"
True since equilateral triangles are isosceles triangles with all angles equal.
"S is a subset of T"
True since scalene triangles are still triangle.
"I ⊂ E"
False since there are isosceles triangles those are not equilateral triangles. Namely triangle with angles 20°, 20°, 140°
"T ⊂ E"
False since not all triangles are equilateral. Scalene triangle is one of counterexamples.
"R ⊂ P"
True since rectangles are parallelograms with right angles.
Final answer: <span>E is a subset of I, </span>S is a subset of T, and R ⊂ P.
Hope this helps.
Think: You're treating the numerator and the denom. in precisely the same way. In doing so you are NOT changing the value of the fraction, only the appearance.
Example: start with 2/3. Mult num. and den. both by 7: 14/21.
2/3 and 14/21 result in precisely the same decimal fraction, showing that the latter set of fractions is equivalent to the former set.
I don’t understand your question can you explain it more
