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weqwewe [10]
3 years ago
12

Is light an external or internal stimulus for plant?explain how plants react to light

Chemistry
1 answer:
allochka39001 [22]3 years ago
3 0
External

Stimuli are anything that causes arousal or enables an object to respond or react.

There are many different kinds of stimuli for which is different for every organism, for example, water, light and carbon dioxide are three stimuli and materials needed for photosynthesis in plants to manifest.
<span>In humans, we have nutrients or food, oxygen and water for us to survive. These are stimuli, eyes need light as a stimuli for it see and function. Nasal receptors needs smell as stimuli caused by molecular reactions of an object as a stimuli. And others. </span>
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What is the empirical formula for a compound if a sample contains 1. 0 g of S and 1. 5 g of O? SO SO3 S2O2 S2O3.
Tcecarenko [31]

The empirical formula of the given compound is \bold{SO_3}.

The correct option is B.

<h3>What is an empirical formula?</h3>

The empirical formula of a chemical compound is the simplest whole-number ratio of atoms contained in the substance.

Given,

1.0 g of S

1.5 g of O

To calculate the empirical formula, we will divide the masses of the elements by their atomic weight.

For sulfur

\bold{\dfrac{1.0}{32} =0.03125\; mol}

For oxygen

\bold{\dfrac{1.5}{16} =0.09375\; mol}

Now, divide the greater value of mole came by the smaller value

\bold{\dfrac{0.09375\; mol}{0.03125\;mol} = 3}

Thus, the empirical formula for the given compound is 1 for S and 3 for O

\bold{SO_3}

Learn more about empirical formula, here:

brainly.com/question/11588623

7 0
2 years ago
What is the ionic &amp; net ionic equation of and their properties (aq, s, l, g) :
alexdok [17]

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6 0
3 years ago
Which ion has the lower ratio of charge to volume? Explain.<br> (b) Sc³⁺ or Ca²⁺
WINSTONCH [101]

Ca²⁺ion has a lower ratio of charge to volume.

The charge density of an ion is defined as the ratio of the charge of an ion to its volume. Scandium ion has high charge density than calcium ions. The charge density of an ion is defined as the ratio of the charge of an ion to its volume.

Charge density also depends on the size of the ion and valence electrons. The volume of an ion increases with its size. It is inversely proportional to ion volume and directly proportional to charge magnitude. Scandium and calcium are IV periodic elements with atomic numbers of 21 and 20 respectively. Scandium loses three electrons and has a +3 charge and calcium is a divalent cation. Hence, the Scandium ion has high charge density than the calcium ion.

Learn more about charge density here: brainly.com/question/12968377

#SPJ4

4 0
2 years ago
Consider the reaction between hydrazine and hydrogen to produce ammonia, N2H4(g)+H2(g)→2NH3(g). Use enthalpies of formation and
kupik [55]

Answer:

The enthalpy of the nitrogen-nitrogen bond in N2H4 is 162.6 kJ

Explanation:

For the reaction: N2H4(g)+H2(g)→2NH3(g), the enthalpy change of reaction is

ΔH rxn = 2 ΔHºf NH3 - ΔHºf N2H4

but we also know that the ΔH rxn is calculated by accounting   the sum of number of bonds formed and bonds broken as follows:

ΔH rxn = 6H (N-H) + 4 (N-H) + 2H (H-H)  

where H is the bond enthalpy .When bonds are broken H is positive, and negative when formed,  in the product there are 6 N-H bonds , and in the reactants 4 N-H and 1 H-H bonds).

Consulting an appropiate reference handbook or table the following values are used:

ΔHºf (NH3) = -46 kJ/mol

ΔHºf (N2H4) = 95.94 kJ/mol

(The enthalpy of fomation of hydrogen in its standard state is zero)

H (N-H) = 391 kJ

H (H-H) = 432 kJ

H (N-N) = ?

So plugging our values:

ΔH rxn =  2mol ( -46.0 kJ/mol) - 1mol(95.4 kJ/mol) = -187.40 kJ

-187.40 kJ = 6(-391 kJ) + 4 (391 kJ) + 432 +  H(N-N)

-187.40 kJ = -350 kJ + H(N-N)

H(N-N) = 162.6 kJ

7 0
3 years ago
Charge q is 1 unit of distance away from the source charge S. Charge p is six times further away. The force exerted between S an
QveST [7]

Answer:

<u>36 times</u>

Explantaion:

The force exerted between two charged particles is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

In the case of S and q: The distance of separation is 1 unit

F(Sq) α S*q/1²

In the case of S and p: the distance is 6 units

F(Sp) α S*p/6²

therefore:

F(Sq) = 36 * F(Sp)

8 0
2 years ago
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