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satela [25.4K]
2 years ago
15

Explain the effect of strong intermolecular forces on each of these parameters: (a) critical temperature;

Chemistry
1 answer:
Delicious77 [7]2 years ago
7 0
  • (A) The molecules can no longer be condensed because they are moving too quickly at the critical temperature.
  • Because the forces are insufficient to stop molecular motion, this temperature drops with weaker intermolecular forces.
  • Alternately, the critical temperature rises as intermolecular forces increase.

b) The boiling point rises as intermolecular forces do because it becomes harder and more energy-intensive to separate molecules from the liquid phase.

(C) For the same reason as in b), the vapor pressure falls as intermolecular forces rise.

  • Strong intermolecular forces prevent molecules from entering the vapor phase easily at any given temperature, resulting in a decrease in vapor pressure.

d) The heat of vaporization rises as intermolecular forces increase because more energy is required to separate molecules from one another.

Learn more about critical temperature

brainly.com/question/16992351

#SPJ4

<u>The complete question is -</u>

Explain the effect of strong intermolecular forces on each of these parameters: (a) critical temperature, (b) boiling point, (C ) vapor pressure, (d) heat of vaporization

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Option c would be the correct answer
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Which molecule will undergo only london dispersion forces when interacting with other molecules of the same kind?.
Neko [114]

Molecules undergo London dispersion forces:

C_{4}H_{10} is the molecule will undergo only London dispersion forces when interacting with other molecules of the same kind.

What are London dispersion forces?

  • A sort of force that interacts between atoms and molecules that is often electrically symmetric is referred to as a London dispersion force.
  • When viewed from the nucleus, their electron distribution is frequently symmetrical. This dispersion force, which is also known as a transient attractive force, is frequently observed when the locations of the electrons in two nearby atoms cause the atoms to temporarily form dipoles.
  • The bond is polar when there are significant variations between the elements' electronegativities; it is nonpolar when there are similarities. When the molecule's dipole moment is equal to O, it is nonpolar; when it differs from O, it is polar.
  • The force at these molecules is known as the London dispersion force. In nonpolar molecules, the forces are weak, and partial charges must be induced so that they can bond. In polar molecules, partial charges caused by polarity result in a stronger link known as a dipole-dipole. The dipole-dipole is significantly stronger and known as a hydrogen bond if it is connected to a large electronegative atom (F, O, or N). Ionic force is the name for the attraction force at ionic substances.
  • The intermolecular force in the letter an is the London dispersion force because the compound is nonpolar;

<u>Reason for incorrect options:</u>

b: the compound is ionic because Na is a metal and the other part is covalent,

c: two compounds are possible: one is nonpolar and exhibits London dispersion force; the other is polar and exhibits dipole-dipole force; and

d: both compounds exhibit hydrogen bonds (H bonded to O, and H bonded to F).

NOTE: Your question is incomplete, but most probably your full question was, which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind? Which molecule will undergo only London dispersion forces when interacting with other molecules of the same kind?

A. C_{4}H_{10}

B. NaC_{2}H_{3}O_{2}

C. CH_{2}C_{12}

D. C_{2}H_{5}OH HF

Learn more about the London dispersion forces here,

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when you break ice, the ice is still ice.  that water did not change into something else.  when you run a current through copper, the electrons in the copper move due to the voltage but the copper is not changing.  After the circuit stops, the copper wires are still made out of copper (the copper did not undergo a chemical change).  When you melt gold, the gold is only going from solid form to liquid form.  The gold has not changed chemically, it just underwent a phase change.
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