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erastovalidia [21]
3 years ago
6

An iron fence is left unpainted, and it reacts with the oxygen in the air, forming rust. The formation of rust is an oxidation-r

eduction reaction, but it is also an example of a _________ reaction
Chemistry
2 answers:
trapecia [35]3 years ago
5 0
I'm pretty sure it would be a chemical reaction.
IrinaK [193]3 years ago
3 0

Answer: This reaction is a type of synthesis reaction.

Explanation: When iron reacts with oxygen which is available in air, it leads to the formation of a reddish-brown compound known as rust.

This reaction is considered as oxidation-reduction reaction because iron is getting oxidized to Fe^{2+} and oxygen is getting reduced to oxide ion.

Equation of the rust follows:

4Fe(s)+3O_2(g)+nH_2O(l)\rightarrow 2Fe_2O_3.nH_2O

Synthesis reactions are defined as the reactions in which two or more than two reactants combine together to form a single product which can be a molecule or a compound.

The rusting of iron is also considered as a synthesis reaction because iron and oxygen are combining together to form a single compound known as rust.

Both these reactions are a type of Chemical reactions.

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Answer:

A

Explanation:

The correct answer is: A) "A concentric contraction because muscles cause the elbow joint and arm to move"

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Whats 2×2 rhdbdjdjddjdjkdjdbdbfbdbxb​
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The answer might be 4, been a while since I've done third grade math though.

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After the child exhaled all of the gas, it becomes sick
tensa zangetsu [6.8K]
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2 years ago
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The reaction described by H2(g)+I2(g)⟶2HI(g) has an experimentally determined rate law of rate=k[H2][I2] Some proposed mechanism
MatroZZZ [7]

Answer:

Mechanism A and B are consistent with observed rate law

Mechanism A is consistent with the observation of J. H. Sullivan

Explanation:

In a mechanism of a reaction, the rate is determinated by the slow step of the mechanism.

In the proposed mechanisms:

Mechanism A

(1) H2(g)+I2(g)→2HI(g)(one-step reaction)

Mechanism B

(1) I2(g)⇄2I(g)(fast, equilibrium)

(2) H2(g)+2I(g)→2HI(g) (slow)

Mechanism C

(1) I2(g) ⇄ 2I(g)(fast, equilibrium)

(2) I(g)+H2(g) ⇄ HI(g)+H(g) (slow)

(3) H(g)+I(g)→HI(g) (fast)

The rate laws are:

A: rate = k₁ [H2] [I2]

B: rate = k₂ [H2] [I]²

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]

<em>Where K' = K1 * K2</em>

C: rate = k₁ [H2] [I]

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]^1/2

Thus, just <em>mechanism A and B are consistent with observed rate law</em>

In the equilibrium of B, you can see the I-I bond is broken in a fast equilibrium (That means the rupture of the bond is not a determinating step in the reaction), but in mechanism A, the fast rupture of I-I bond could increase in a big way the rate of the reaction. Thus, just <em>mechanism A is consistent with the observation of J. H. Sullivan</em>

5 0
3 years ago
There are two physical properties of minerals that both result in smooth, flat surfaces with specific angles between them. The f
stich3 [128]

Answer:

3. crystal habit and cleavage.

Explanation:

Crystal habit is a distinctive characteristic which is shown in its general shape,  crystallographic forms, how developed each form is.

Cleavage is the ability of a mineral to break in smooth planes parallel to zones of weak bonding. Cleavage in three directions at right angles (90o). Cubic cleavage. Cleavage in three directions not at right angles (120o and 60o).

3 0
3 years ago
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