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erastovalidia [21]
3 years ago
6

An iron fence is left unpainted, and it reacts with the oxygen in the air, forming rust. The formation of rust is an oxidation-r

eduction reaction, but it is also an example of a _________ reaction
Chemistry
2 answers:
trapecia [35]3 years ago
5 0
I'm pretty sure it would be a chemical reaction.
IrinaK [193]3 years ago
3 0

Answer: This reaction is a type of synthesis reaction.

Explanation: When iron reacts with oxygen which is available in air, it leads to the formation of a reddish-brown compound known as rust.

This reaction is considered as oxidation-reduction reaction because iron is getting oxidized to Fe^{2+} and oxygen is getting reduced to oxide ion.

Equation of the rust follows:

4Fe(s)+3O_2(g)+nH_2O(l)\rightarrow 2Fe_2O_3.nH_2O

Synthesis reactions are defined as the reactions in which two or more than two reactants combine together to form a single product which can be a molecule or a compound.

The rusting of iron is also considered as a synthesis reaction because iron and oxygen are combining together to form a single compound known as rust.

Both these reactions are a type of Chemical reactions.

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You are burning wood to heat water for your industrial process. What is the mass of wood required to raise the temperature of 10
natta225 [31]

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18,8kg of wood

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<u><em>q = 3,14x10⁸ J of heat are required</em></u>

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5 0
3 years ago
g If 50.0 mL of a 0.75 M acetic acid solution is titrated with 1.0 M sodium hydroxide, what is the pH after 10.0 mL of NaOH have
V125BC [204]

Answer:

pH = 2.66

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  • Acetic Acid + NaOH → Sodium Acetate + H₂O

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  • 0.75 M Acetic acid * 50.0 mL = 37.5 mmol acetic acid
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We<u> calculate how many acetic acid moles remain after the reaction</u>:

  • 37.5 mmol - 10 mmol = 27.5 mmol acetic acid

We now <u>calculate the molar concentration of acetic acid after the reaction</u>:

27.5 mmol / (50.0 mL + 10.0 mL) = 0.458 M

Then we <u>calculate [H⁺]</u>, using the<em> following formula for weak acid solutions</em>:

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Finally we <u>calculate the pH</u>:

  • pH = -log[H⁺]
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