Answer:
C
Step-by-step explanation:
The domain is all real numbers, and the range is all integers that are multiples of 3. This is right I took the test.
One acre of land is equal to 4046.86 sq.m.
To know how far they can throw the ball from corner to corner can be interpreted in two ways: throwing the ball diagonally across the field or throwing the ball horizontally across the field. For the first question, since the field is a square, you can use the equation Diagonal of Square = A x sq.root of 2.
In this case, the answer would be 89.97 m.
If the ball is thrown horizontally across the field, then you would only need to know the length of one side of the square, which is the square root of the area. Doing this would give you the answer 63.61 m.
9514 1404 393
Answer:
D.
Step-by-step explanation:
The wording "when x is an appropriate value" is irrelevant to this question. That phrase should be ignored. (You may want to report this to your teacher.)
When you look at the answer choices, you see that all of them are negative except the last one (D). When you look at the problem fraction, you see that it is positive.
The only reasonable choice is D.
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Your calculator can check this for you.
√12/(√3 +3) ≈ 3.4641/(1.7321 +3)
= 3.4641/4.7321 ≈ 0.7321 = -1 +√3
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If you want to "rationalize the denominator", then multiply numerator and denominator by the conjugate of the denominator. The conjugate is formed by switching the sign between terms.

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<em>Additional comment</em>
We "rationalize the denominator" in this way to take advantage of the relation ...
(a -b)(a +b) = a² -b²
Using this gets rid of the irrational root in the denominator, hence "rationalizes" the denominator.
We could also have multiplied by (3 -√3)/(3 -√3). This would have made the denominator positive, instead of negative. However, I chose to use (√3 -3) so you could see that all we did was change the sign from (√3 +3).
For this case we have the following type of equations:
Quadratic equation:

Linear equation:

We observe that when equating the equations we have:

Rewriting we have:

We obtain a polynomial of second degree, therefore, the maximum number of solutions that we can obtain is 2.
Answer:
The greatest number of possible solutions to this system is:
c.2