Answer:
Step-by-step explanation:
He will actually need to wait for 12 weeks. And that is because if you look at the multiples of 6 and 4 and you'll notice that 12 is the lowest common multiple between them. So you start counting from 6 and 4 at the same time until you notice the LCM of these two numbers then on which ever you number you settle on is how long he will need to wait.
Answer:
d=-210
Step-by-step explanation:
multiply 15 to both sides
-14*15 =-210
the 15 on the side with d cancels
Now you have d=-210
Hope this helps!
47268.569 ttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttttt
Answer:
option B
Step-by-step explanation:
Rule:output=input -2
LEts analyze the table
we use the input and apply the rule to get the output
LEts subtract 2 from input to get the output
Input Rule (input -2 ) Output
-3 -3-2 -5
-7 -7-2 -9
6 6-2 4
Option B matches with our table
Answer:
See picture and explanation below.
Step-by-step explanation:
With this information, the matrix A that you can find is the transformation matrix of T. The matrix A is useful because T(x)=Av for all v in the domain of T.
A is defined as ![T=([T(v_1)] [T(v_2] [T(v_3)])\text{ where }[T(v_i)]](https://tex.z-dn.net/?f=T%3D%28%5BT%28v_1%29%5D%20%5BT%28v_2%5D%20%5BT%28v_3%29%5D%29%5Ctext%7B%20where%20%7D%5BT%28v_i%29%5D)
denotes the vector of coordinates of 
respect to the basis 
(we can apply this definition because 
forms a basis for the domain of T).
The vector of coordinates can be computed in the following way: if 
then ![[T(v_i)]=(a_1,a_2,a_3)^t](https://tex.z-dn.net/?f=%5BT%28v_i%29%5D%3D%28a_1%2Ca_2%2Ca_3%29%5Et)
.
Note that we have all the required information: 
then ![[T(v_1)]=(0,1,0)^t](https://tex.z-dn.net/?f=%5BT%28v_1%29%5D%3D%280%2C1%2C0%29%5Et)
hence ![[T(v_2)]=[T(v_3)]=(1,0,0)^t](https://tex.z-dn.net/?f=%5BT%28v_2%29%5D%3D%5BT%28v_3%29%5D%3D%281%2C0%2C0%29%5Et)
The matrix A is on the picture attached, with the multiplication A(1,1,1).
Finally, to obtain the output required at the end, use the properties of a linear transformation and the outputs given:
In this last case, we can either use the linearity of T or multiply by A.
