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Ipatiy [6.2K]
2 years ago
12

If a polygon has 189 diagonals how many sides does the polygon have ?

Mathematics
2 answers:
Damm [24]2 years ago
7 0
N(n-3)/2=189
n(n-3)=378
n^2-3n-378=0
n=21
Natali [406]2 years ago
5 0
<span>(n take 2) minus n = 189 
n(n-3)/2 = 189 
n(n-3) = 378 
n^2-3n-378 = 0 
n=21

</span>
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At a construction job for a mall there are 45 painters. Of these painters, 18 of them are painting the interior of the mall. Wha
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Question 7 of 10
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g(x) = –3(x + 6)2 + 48.

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The graph of f(x) = x2 is shifted right 6 units. The graph of f(x) = x2 is shifted down 48 units. The graph of f(x) = x2 is reflected over the y-axis.

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Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

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c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

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Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

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5 0
3 years ago
Factor this expression completely.<br><br> 39x − 52y + 13
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Answer:

13(3x-4y+1)

Step-by-step explanation:

Rewrite 52 as (4)(13)

Rewrite 39 as (3)(13)

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Then factor out the common term 13

13(3x-4y+1)

That is your answer!

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