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Ipatiy [6.2K]
2 years ago
12

If a polygon has 189 diagonals how many sides does the polygon have ?

Mathematics
2 answers:
Damm [24]2 years ago
7 0
N(n-3)/2=189
n(n-3)=378
n^2-3n-378=0
n=21
Natali [406]2 years ago
5 0
<span>(n take 2) minus n = 189 
n(n-3)/2 = 189 
n(n-3) = 378 
n^2-3n-378 = 0 
n=21

</span>
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