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Norma-Jean [14]
3 years ago
12

How do i read a curve graph need help !!!

Mathematics
1 answer:
drek231 [11]3 years ago
7 0

Answer:

Let's use the plot to the right as an example for reading data from a graph. This plot shows travel times as related to distance for P-waves (red curve) and S-waves (blue curve) from the epicenter of an earthquake. P- and S-waves are two types of waves that are generated by earthquakes; P-waves travel faster than S-waves.  I hope this helps.

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Y’all please give me the answer to this. (7 questions) have to show work.Geometry. Will mark brainliest.
topjm [15]

Answer:

Step-by-step explanation:

Sweet. Get to answer finally. I was the guy commenting on your other post.

1. 72

2. 46

3. 99

4. Same side interior angles are supplementary

5. alternate interior angles are equal to each other so set up the x expressions equal to each other. 5x-7=3x+17. Solve for x

5x-7=3x+17

2x=24

x=12

plug it in for the 5x-7 and get an angle.. 5(12)-7

60-7

53.

The 5x-7 and the 4y+3 is supplementary.

so 53+3+4y=180. combine the 2 and set them equal to 180 to find y

56+4y=180

124=4y

y=31

And now we find the angle of 6. We know that corresponding angles are equal and the y expression and angle 6 are corresponding angles

so plug in your answer for y in the expression..

4(31)+3 = 127.

so angle 6 is 127

6 0
3 years ago
A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, h_o=5\ ft

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

h=-16t^2+vt+h_0

Putting all the values,

h=-16t^2+60t+5 .....(1)

For maximum height, put

\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s

Put t = 1.875 in equation (1)

h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m

So, the maximum height reached by the ball is 61.25 m.

8 0
3 years ago
PLEASE SOMEONE PLEASEE HELP ME. NO LINKSSSS <3
Levart [38]

Answer:

C and E

Step-by-step explanation:

JUST MULTYPLY:):):)

3 0
3 years ago
Which integer did he write?
cluponka [151]
-3 is the integer Phillip wrote
7 0
3 years ago
Read 2 more answers
Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
4 years ago
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