Answer:
f(x) = 4x^2 + 2x - 4.
Step-by-step explanation:
Let the quadratic function be y = f(x) = ax^2 + bx + c.
For the point (-2, 8) ( x = -2 when y = 8) we have:
a(-2)^2 + (-2)b + c = 8
4a - 2b + c = 8 For (0, -4) we have:
0 + 0 + c = -4 so c = -4. For (4, 68) we have:
16a + 4b + c = 68
So we have 2 systems of equations in a and b ( plugging in c = -4):
4a - 2b - 4 = 8
16a + 4b - 4 = 68
4a - 2b = 12
16a + 4b = 72 Multiplying 4a - 2b = 12 by 2 we get:
8a - 4b = 24
Adding the last 2 equations:
24a = 96
a = 4
Now plugging a = 4 and c = -4 in the first equation:
4(4) - 2b - 4 = 8
-2b = 8 - 16 + 4 = -4
b = 2.
JM=12
JL= 14
MN=?
MK=?
VT= 11
UV= 9
RS=?
ST=?
GF=23
HF=20
GH=?
GE=?
M<1=?
M<2=?
M<3=?
M<4=?
M<5=?
M<6=?
M<7=?
M<8 = 90 degrees
WXZ = 34 degrees
WVZ=90 degrees
ZYW= 56 degrees
These are the only answers I knew, I’m sorry I couldn’t find the rest. If I do find more answers, I’ll comment them.
Answer:
18b+12
Step-by-step explanation:
6x3=18,6x2=12 so it's 18b(keep the variable)+12
Answer:
The value of the equation
.
Step-by-step explanation:
Consider the provided equation.

We need to solve the provided equation for y.
Subtract 3x from both side.


Divide both sides by 7.


Hence, the value of the equation is
.