When we use arcsine, we are finding the angle while giving the trigonometric ratio.
Arcsin(u) = theta can be rewritten as:
sin(theta) = u
Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.
We can use Pythagorean Theorem to find the adjacent (x value).
1^2 - u^2 = x^2
x = sqrt(1-u^2)
Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).
Cosine is adjacent over hypotenuse.
So our answer is sqrt(1-u^2)/1
Or just sqrt(1-u^2)
9514 1404 393
Answer:
2) true
3) X = -19/48
4) Y = 27/56
Step-by-step explanation:
3) Subtract 5/6 from both sides
X = 7/16 -5/6 = (7·6 -16·5)/(16·6) = (42 -80)/96
X = -19/48
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4) Subtract 1/7 from both sides
Y = 5/8 -1/7 = (5·7 -8·1)/(8·7)
Y = 27/56
Answer:
HERES YOUR ASSIGNMENT! I EDITED IT ON MICROSOFT SO THAT I CAN SCREENSHOT IT AND SEND IT TO YOU...I HOPE IT HELPS :)
<h3>ARIGATO OZAIMASU!!!</h3>
