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Goryan [66]
3 years ago
5

A bag has 2 red marbles, 1 blue marble and 4 gold marbles. What is the probability of drawing two gold marbles, if the first mar

ble is replaced after it is drawn?
A) 2/7
B)16/49
C)4/7
D)7/13
Mathematics
1 answer:
Svet_ta [14]3 years ago
3 0

|\Omega|=7^2=49\\ |A|=4^2=16\\\\ P(A)=\dfrac{16}{49}\Rightarrow \text{B}

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Verizon [17]
-1+1=0. So your answer is -1 and 1
3 0
2 years ago
The amount of oil it takes to cover the bottom of a frying pan.
murzikaleks [220]

Answer:

about 1 cup maybe less

Step-by-step explanation:

8 0
2 years ago
A sporting goods store specializes in mountain bikes. Each week, two dozen mountain bikes are randomly selected from the store's
JulijaS [17]

Answer:

A

Step-by-step explanation:

A population is a set of similar items or events which is of interest for some question or experiment.

4 0
1 year ago
A box with a square base and open top must have a volume of 32,000 cm3. find the dimensions of the box that mini- mize the amoun
zmey [24]
Alrighty


squaer base so length=width, nice


v=lwh
but in this case, l=w, so replace l with w
V=w²h

and volume is 32000
32000=w²h


the amount of materials is the surface area
note that there is no top
so
SA=LW+2H(L+W)
L=W so
SA=W²+2H(2W)
SA=W²+4HW

alrighty

we gots
SA=W²+4HW and
32000=W²H

we want to minimize the square foottage
get rid of one of the variables
32000=W²H
solve for H
32000/W²=H
subsitute

SA=W²+4WH
SA=W²+4W(32000/W²)
SA=W²+128000/W

take derivitive to find the minimum
dSA/dW=2W-128000/W²
where does it equal 0?

0=2W-1280000/W²
128000/W²=2W
128000=2W³
64000=W³
40=W

so sub back
32000/W²=H
32000/(40)²=H
32000/(1600)=H
20=H

the box is 20cm height and the width and length are 40cm
7 0
3 years ago
Is X-13=x+1 true or false
Black_prince [1.1K]

Answer: FALSE.

Step-by-step explanation:

Given the following equation provided in the exercise:

x-13=x+1

You need to solve for the variable "x".

In order to solve for "x" you can folllow the steps shown below:

1. You must apply the Addition property of equality and add 13 to both sides of the equation. Then:

x-13+(13)=x+1+(13)\\\\x=x+14

2. Finally you need to apply the Subtraction property of equality and subtract "x" from both sides of the equation. So you get:

x-(x)=x+14-(x)\\\\0=14\ (FALSE)

Therefore, as you can observe, the given equation has no solutions.

3 0
3 years ago
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