All categories

2 years ago

20. What is the value of y in the algebraic

Mathematics

1 answer:

Dennis_Churaev [7]2 years ago

7 0

Answer: 17/7

Step-by-step explanation: Step 1: Simplify both sides of the equation. y+4/15 + 2y−5/5 = 2/5 1/15 y+ 4/15 + 2/5 y+−1= 2/5 (Distribute) ( 1/15 y+ 2/5 y)+( 4/15 +−1)= 2/5 (Combine Like Terms) 7/15 y+ −11/15 = 2/5 7/15 y+ −11/15 = 2/5 Step 2: Add 11/15 to both sides. 7/15 y+ −11/15 + 11/15 = 2/5 + 11/15 7 15 y= 17/15

You might be interested in

Factor completely: 12a^2b–18ab^2–30ab^3

Goryan [66]

Answer:

6ab(2a-3b-5b²)

Step-by-step explanation:

6(2a²b-3ab²-5ab³)

6a(2ab-3b²-5b³)

6ab(2a-3b-5b²)

7 0

2 years ago

Consider the differential equation:

Wewaii [24]

(a) Take the Laplace transform of both sides:

$2y''(t)+ty'(t)-2y(t)=14$

$\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s$

where the transform of $ty'(t)$ comes from

$L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)$

This yields the linear ODE,

$-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s$

Divides both sides by $-s$ :

$Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}$

Find the integrating factor:

$\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C$

Multiply both sides of the ODE by $e^{3\ln|s|-s^2}=s^3e^{-s^2}$ :

$s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}$

The left side condenses into the derivative of a product:

$\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}$

Integrate both sides and solve for $Y(s)$ :

$s^3e^{-s^2}Y(s)=7e^{-s^2}+C$

$Y(s)=\dfrac{7+Ce^{s^2}}{s^3}$

(b) Taking the inverse transform of both sides gives

$y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]$

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that $\frac{7t^2}2$ is one solution to the original ODE.