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Mashcka [7]
3 years ago
5

What is the slope of the line?

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
4 0
The answer Would be C) -1. because of the equations y2-y1 and x2-x1
The answer would 7/-7 therefore when you simplify the number it would be -1.
Hope this helped :)
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Please help me with number 6
Genrish500 [490]
30=(10*3*x)/2
*2 *2
60=10*3*x
60=30x
60/30=30x/30
2=x
7 0
3 years ago
The amount of calories consumed by customers at the Chinese buffet is normally distributed with mean 2617 and standard deviation
Eduardwww [97]

Answer:

a) N(2617, 586)

b) 0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c) 0.4013 = 40.13% of the customers consume over 2764 calories

d) 3981 calories.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 2617, \sigma = 586

a. What is the distribution of X?

Here we first place the mean, then the standard deviation.

N(2617, 586)

b. Find the probability that the customer consumes less than 2409 calories.

This is the pvalue of Z when X = 2409. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2409 - 2617}{586}

Z = -0.355

Z = -0.355 has a pvalue of 0.3613

0.3613 = 36.13% probability that the customer consumes less than 2409 calories.

c. What proportion of the customers consume over 2764 calories?

This is 1 subtracted by the pvalue of Z when X = 2764. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{2764 - 2617}{586}

Z = 0.25

Z = 0.25 has a pvalue of 0.5987

1 - 0.5987 = 0.4013

0.4013 = 40.13% of the customers consume over 2764 calories

d. The Piggy award will given out to the 1% of customers who consume the most calories. What is the fewest number of calories a person must consume to receive the Piggy award?

Top 1%, so the 100-1 = 99th percentile.

The 99th percentile is the value of X when Z has a pvalue of 0.99. So it is X when Z = 2.327. So

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 2617}{586}

X - 2617 = 2.327*586

X = 3980.6

Rounding to the nearest calorie, 3981 calories.

7 0
3 years ago
Need urgent help in mathematics!! Will mark brainliest!!!! PLEASE look at the photo to answer the question .....
Mrrafil [7]

3.1

the number of trucks reading horizontally from the vertical scale is

2 + 2 + 3 + 3 + 3 + 4 + 5 = 22

average number of trucks = \frac{22}{7} = 3.1 ( to 1 dec. place)


3 0
3 years ago
Jena's income is $1600 a month, and she plans to budget 1/3 of her income for rent and 1/8 of her income for groceries. Step 2 o
WARRIOR [948]

Answer:

Jena spends $ 733. 33 on her rent and groceries  altogether per month.

Step-by-step explanation:

Jena's total income in a month= $1600

Here , expenditure on rent = (1/3) of her income

So, now one- third of her income $1600 is  

= \frac{1}{3}  \times 1600 = 533.33

or, (1/3) of her salary is  $533. 33

Hence, Jena spends $ 533. 33 on her rent monthly.

Now, her expenditure on groceries = (1/8) of her income

So, now one- eighth of her income $1600 is  

= \frac{1}{8}  \times 1600 = 200

or, (1/8) of her salary is $ 200.

Jena spends  $ 200. on her groceries  monthly.

So, Total expenditure  = Expenditure on rent + Expenditure on groceries

= $533. 33 + $200 = $733.33

Hence, Jena spends $ 733. 33 on her rent and groceries  altogether per month.

7 0
3 years ago
I need help please thank you
otez555 [7]

Answer: For question 2 I think it would be C

Step-by-step explanation:

6 0
3 years ago
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