Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
5/6
Step-by-step explanation:
Let 'x' be number of females in the course
Number of males= 5x
total number of students= 5x+x
= 6x
Fraction of male students= number of male students/total number of students
= 5x/6x
= 5/6
Answer:
You need four squares.
On the top left square, you put the number 20 over it, and the number 30 to it's left. Put the number 600 in the square.
Next, the bottom left square. But the number 8 on the left side of the square, and put the number 160 in the square.
Now, the top right box. put the number 4 over it, and fill it with the number 120.
Last, fill the bottom right square with the number 32.
Answer:
-7g - 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define expression</u>
-3(5g + 1) + 8g
<u>Step 2: Simplify</u>
- Distribute -3: -15g - 3 + 8g
- Combine like terms: -7g - 3
Im confused what the question is...
