2 years ago

Help i need this answer by tomorrow

Mathematics

1 answer:

Reika [66]2 years ago

8 0

I think that it could be B or A

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Given: △ACM, m∠C=90°, CP ⊥ AM

larisa86 [58]

Answer: The answer is $3\dfrac{4}{7}.$

Step-by-step explanation: Given in the question that ΔAM is a right-angled triangle, where ∠C = 90°, CP ⊥ AM, AC : CM = 3 : 4 and MP - AP = 1. We are to find AM.

Let, AC = 3x and CM = 4x.

In the right-angled triangle ACM, we have

$AM^2=AC^2+CM^2=(3x)^2+(4x)^2=9x^2+16x^2=25x^2\\\\\Rightarrow AM=5x.$

Now,

$AM=AP+PM=AP+(AP+1)\\\\\Rightarrow 2AP=AM-1\\\\\Rightarrow 2AP=5x-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(A)$

Now, since CP ⊥ AM, so ΔACP and ΔMCP are both right-angled triangles.

So,

$CP^2=AC^2-AP^2=CM^2-MP^2\\\\\Rightarrow (3x)^2-AP^2=(4x)^2-(AP+1)^2\\\\\Rightarrow 9x^2-AP^2=16x^2-AP^2-2AP-1\\\\\Rightarrow 2AP=7x^2-1.~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(B)$

Comparing equations (A) and (B), we have

$5x-1=7x^2-1\\\\\Rightarrow 5x=7x^2\\\\\Rightarrow x=\dfrac{5}{7},~\textup{since }x\neq 0.$

Thus,

$AM=5\times\dfrac{5}{7}=\dfrac{25}{7}=3\dfrac{4}{7}.$

8 0

3 years ago

Cole bought a cutting board online. It cost $23 plus 10% shipping and handling. What was the total cost?

Rashid [163]

Cole would pay $25.30
Because 23/10=2.3
2.3+23=25.3
Hope this helped

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2 years ago

Jonas is doing a science experiment with his class. The teacher has 21 fluid ounce of pond water to share equally with 10 pairs

tiny-mole [99]

2.1 ounces because you divide 21 by 10 which equals 2.1

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3 years ago

A graph titled Monthly Sales and Advertising Costs has Advertising Costs (1,000 dollars) on the x-axis and sales (1,000 dollars)

ludmilkaskok [199]

Answer: The awnser is A,C,E

I just did it and got it right

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2 years ago

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16 is 10% of what number

marusya05 [52]

let's say is 16% of "x", meaning "x" is the 100%.

we know "x" is 100% and 16% of it is 10, so

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 16&10 \end{array}\implies \cfrac{x}{16}=\cfrac{100}{10}\implies \cfrac{x}{16}=10\implies x = 160$

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3 years ago

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