Answer:
<u>ALTERNATIVE 1</u>
a. Find the profit function in terms of x.
P(x) = R(x) - C(x)
P(x) = (-60x² + 275x) - (50000 + 30x)
P(x) = -60x² + 245x - 50000
b. Find the marginal cost as a function of x.
C(x) = 50000 + 30x
C'(x) = 0 + 30 = 30
c. Find the revenue function in terms of x.
R(x) = x · p
R(x) = x · (275 - 60x)
R(x) = -60x² + 275x
d. Find the marginal revenue function in terms of x.
R'(x) = (-60 · 2x) + 275
R'(x) = -120x + 275
The answers do not make a lot of sense, specially the profit and marginal revenue functions. I believe that the question was not copied correctly and the price function should be p = 275 - x/60
<u>ALTERNATIVE 2</u>
a. Find the profit function in terms of x.
P(x) = R(x) - C(x)
P(x) = (-x²/60 + 275x) - (50000 + 30x)
P(x) = -x²/60 + 245x - 50000
b. Find the marginal cost as a function of x.
C(x) = 50000 + 30x
C'(x) = 0 + 30 = 30
c. Find the revenue function in terms of x.
R(x) = x · p
R(x) = x · (275 - x/60)
R(x) = -x²/60 + 275x
d. Find the marginal revenue function in terms of x.
R(x) = -x²/60 + 275x
R'(x) = -x/30 + 275
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
To find the initial amount, put 0 where t is in the formula and do the arithmetic.
A(0) = 523(1/2)^0 = 523(1) = 523
The initial amount is 523 grams.
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To find the amount remaining after 100 years, put 100 where t is in the formula and do the arithmetic.
A(100) = 523(1/2)^(100/30) ≈ 523(0.0992123) ≈ 52
About 52 grams will remain after 100 years.
Answer:
The pre-image
Step-by-step explanation:
Hope this helps ya!
